Answer:
where is your question ?????????
You should see the denominator of the function in this case.
6x ^ 2-7x-3
We see where the denominator becomes zero:
6x ^ 2-7x-3 = 0
x1 = 3/2
x2 = -1 / 3
The function is discontinuous in those two points.
Therefore, it has vertical asymptotes in:
x1 = 3/2
x2 = -1 / 3
answer:
has vertical asymptotes in:
x1 = 3/2
x2 = -1 / 3
option 1
Answer:
Step-by-step explanation:
First, we can divide out the common factor, 6
Now we complete the square
You didn't put the questions
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