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Jlenok [28]
3 years ago
5

4/5 of the senior class went to prom if 324 seniors went to prom how many are there in the senior class

Mathematics
1 answer:
Sedbober [7]3 years ago
5 0

Answer:

405

Step-by-step explanation:

324 seniors is 4/5 of all seniors. To find how many 5/5 of the seniors is, we find 1/5 and multiply it by 5. Since 4/5 is 4 times 1/5, divide 324 by 4. The answer is 81, which is 1/5 of the seniors. Multiply 81 by 5 to get all 5/5. 81 * 5 is 405

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mihalych1998 [28]
7:
Parallel lines have the same slope
y = -3x + b
Plug in the x and y values from the point
5 = -3(-4) + b
5 = 12 + b
-7 = b
Answer to 7: y = -3x -7

8:
Perpendicular lines have opposite reciprocal slopes
y = -2x + b
Plug in x and y from the point
-6 = -2(7) + b
-6 = -14 + b
8 = b
Answer to 8: y = -2x + 8
3 0
2 years ago
Write an equation of a line that passes through (1,1)and (6,6)
Ghella [55]

Answer:

y=x

Step-by-step explanation:

When y=x, then the line goes up 1 and right 1.

7 0
2 years ago
7(x + 4) + 5(x-6) please expand and simplify
Neporo4naja [7]

Answer:

12x − 2

Step-by-step explanation:

7(x+4)+5(x−6)

Distribute:

=(7)(x) + (7)(4) + (5)(x) + (5)(−6)

=7x + 28 + 5x − 30

Combine Like Terms:

=7x + 28 + 5x − 30

=(7x+5x) + (28−30)

= 12x − 2

8 0
3 years ago
Read 2 more answers
2x-1<br> Evaluate the algebraic expressions for the given values of the variable
igor_vitrenko [27]
<span>An algebraic expression is an expression constructed from a number of constants and variables utilizing algebraic operations. These algebraic operations are addition, subtraction, multiplication, division, and exponentiation. A constant is constant, so its value is unchanged. A variable changes based on the value provided. In the provided example, 2x-1, there are two constants, "2" and "1", and one variable "x." The algebraic operations utilized are multiplication and subtraction. In order to evaluate the value of the algebraic expression, the given value for the variable must be substituted for the variable x, and then the algebraic operations executed to obtain the answer. For instance, if you were told that the value of x in this case was 2, then you would substitute the value 2 for x and perform the described operations. Remember to follow the order of operations when evaluating an algebraic expression! 2x-1 for x=2 2(2) - 1 4 - 1 3 is the answer. Remember, even though the multiplication operation is not explicitly stated, it is implied that a constant attached to a variable (termed a coefficient) is multiplied with the value of the variable.</span>
5 0
3 years ago
Help pls what's the common difference
horsena [70]

<u><em>Answer: </em></u>

#9: 5

#10: -2

#11: -1.5

<em><u>Step-by-step explanation:</u></em>

<em><u>#9:</u></em> 3,8,13,18,23,(28),(33),(38),.. <em>Go up by 5 each time, so the common difference is </em><u><em>5</em></u><em>.</em>

<u><em>#10:</em></u> 11,9,7,5,3,(1),(-1),(-3),... <em>Go down </em><em>(-)</em><em> by 2 each time, so the common difference is </em><u><em>-2</em></u><em>.</em>

<u><em>#11:</em></u> 3, 1.5, 0, -1.5, -3, (-4.5), (-6), (-7.5),... <em>Go down </em><em>(-) </em><em>by 1.5 each time, so the common difference is </em><u><em>-1.5</em></u><em>.</em>

7 0
3 years ago
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