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baherus [9]
4 years ago
8

Summer exercises for 0.5 hour on Monday Wednesday and Friday each week. How many hours will she exercise in four weeks

Mathematics
2 answers:
Sati [7]4 years ago
6 0

Answer:

She will exercise for 6 hours in four weeks.

Step-by-step explanation:

Summer exercises for 0.5 hour on Monday, 0.5 hour on Wednesday, and 0.5 hour on Friday. There are 3 days where she exercises for 0.5 hour.

3 days X 0.5h = 1.5h each week

For four weeks, multiply the hours each week by 4.

1.5h X 4 weeks = 6h

Therefore Summer will exercise for 6 hours over the course of 4 weeks.

rusak2 [61]4 years ago
3 0

Answer:

6 hours

Step-by-step explanation:

We know that Summer exercises for 0.5 (Or a half) hour every day, three days a week (Monday, Wednesday, Friday). We need to found out how many hours she exercises in 4 weeks.

To solve this we first find out how many hours she exercises in one week. To do so, we set up an equation like this:

(Time exercising) x (# of days exercising) = (Hours spent exercising in one week)

Plug in the given numbers:

0.5 x 3 = 1.5 hours

If we know she exercises 1.5 (Or one and a half) hours in 1 week, we multiply this number by 4 to find out how many hours she exercises in 4 weeks. This can be shown in an equation like this:

1.5 x 4 = 6

So Summer will exercise for 6 hours in 4 weeks.

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gulaghasi [49]
<< Add .\frac{-4}{5} to the left and right of the equation, multiple and make ''opposite multiplation'' to find x.

A) \frac{4}{5x}. \frac{-4}{5} = 8.  \frac{-4}{5} &#10;
\frac{16}{25x} = \frac{-32}{5}
25x.(-32)= (-16).5
-800x= -80

**to leave x alone and positive, you must divide to -800.
x=  \frac{-80}{-800}
x=  \frac{1}{10}
= INCORRECT

B) \frac{4}{5x} . \frac{1}{5} = 8. \frac{1}{5} &#10;
\frac{4}{25x} = \frac{8}{5}
25x.8= 4.5
200x=20&#10;
x=  \frac{20}{200} =  \frac{1}{10}


C)\frac{4}{5x} . \frac{5}{4}=  \frac{8.5}{4}
\frac{1}{x} = \frac{40}{4}
\frac{1}{x} =10
10x=1
x= \frac{1}{10}


D) \frac{4.5}{5x}  = 8.5
\frac{4}{x} = 40
40x= 4
x= \frac{4}{40} = 1/10

I think there is a problem with the options :D







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