615 - 6 = 609
963 - 6 = 957
609=3×3×29
957=3×11×29
HCF=3×29=87
The largest number that divides 615 and 963 leaving remainder 6 in both numbers is 87.
1st use the Step! Please, Excuse, My, Dear, Aunt, Sally! Ehich also means (PEMDAS) Parenthesis (), Exponents ", Multiple ×, Division÷, Addition+, and Subtraction-. Than your going to solve! (3n+5)×9=n×7
27n+45=7n
27n-7n=-45
20n=-45
n=-45/20= -9/4
Answer:
D
Step-by-step explanation:
y=x+3/8x
Answer:
c
Step-by-step explanation: