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astra-53 [7]
3 years ago
13

Evaluate. 10 • (-4) Enter your answer in the box.

Mathematics
2 answers:
wolverine [178]3 years ago
4 0

Answer:

it is -40

Step-by-step explanation:

yes yes right????

Mashutka [201]3 years ago
4 0
The answer to this is -40.
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How do you factorise fully x³-x
Harman [31]

Answer:

=x³-x

=x(x²-1)

=x(x²-1²)

=x(x+1)(x-1)

hope it helps.

4 0
3 years ago
A panda and a giraffe start moving towards each other when they are 300 feet apart. The panda is running at a speed of P feet pe
liq [111]

Answer:

(2P + G) feet/min

Step-by-step explanation:

Speed of the panda = P

Speed of the giraffe = P + G

Thus,

Speed of Panda + Speed of Giraffe = approaching time

= P + P + G

= <u>2P + G</u>

Thus, The panda and the giraffe are approaching each other at a rate

of <u>(2P + G) ft/min</u>

<u></u>

<em>Hope it helps :)</em>

6 0
3 years ago
What is the area of the shaded triangle?
Rzqust [24]

Answer:30

Step-by-step explanation: act like both of the triangles are there, that is a rectangle 6 times 10 equals 60. 60 divided by 2 is 30

6 0
3 years ago
Help Q-Q 7/10c =4 1/5
shepuryov [24]

\huge\mathfrak\green{answer}

= q -   \frac{q7}{10} c =  \frac{41}{5}

\red{multiply}

= q -  \frac{cq7}{10} =  \frac{41}{5}

\red{subtract \: q \: from \: both \: sides}

= q -  \frac{cq7}{10}  - q =  \frac{41}{5} - q

\red{now \: simplify}

=  -  \frac{cq7}{10}  =  \frac{41}{5}  - q

\red{multiply \: 10 \: both \: sides}

= 10( -  \frac{cq7}{10} ) = 10. \frac{41}{5}  - 10q

\red{simplify}

=  - cq7 = 82 - 10q

\red{now \: divide}

=  \frac{ - cq7}{ - q7}  -  \frac{82}{ - q7}  -  \frac{10q}{ - q7}

\red{simplify}

= c =   - \frac{82 - 10q}{q7} (q≠0)

Brainliest? :) (I'd really appreciate if you mark me as brainliest)

\huge\mathfrak\green{thank \: you}

5 0
3 years ago
Read 2 more answers
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
3 years ago
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