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2 years ago

Which value is a solution for the equation tan x/2 = -1?

Mathematics

2 answers:

Luba_88 [7]2 years ago

4 0

Answer:

Step-by-step explanation:

What we have to do is to find the arc tan

x/2 = arc tan (-1)

tan is negative on the 4th and second quadrant

arc tan (-1) = 135 or 315

pi is 180 degrees

so we have;

135 is 3 pi/4

multiplied by the 2

= 6 pi/4 which is 3 pi/2

315 is 7 pi/4 which is same as 7 pi/2 when we multiply by 2

zysi [14]2 years ago

3 0

Answer:

the answer is d

You might be interested in

Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer

QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

7 0

2 years ago

How can I write repeated multiplication using powers?

andrew-mc [135]

Example: 3^4 would be 3x3x3x3

8 0

3 years ago

It costs $10.99 per month for an online video streaming service. Jackie watched 28 videos in one month. What was the price per v

Kitty [74]

Answer:

Assuming it's actually charging per video, and not just for a subscription, the cost per video would be .40 (40 cents per movie)

Step-by-step explanation:

10.99 / 28 =

.3925

Which rounded up is .40

3 0

3 years ago

M is directly proportional to r cubed when r = 4, m = 160. Find the value of r when m = 540

Anarel [89]

Answer:

r = 6

Step-by-step explanation:

Given that M is directly proportional to r³ then the equation relating them is

M = kr³ ← k is the constant of proportionality

To find k use the condition r = 4 when M = 160

k = $\frac{M}{r^3}$ = $\frac{160}{64}$ = 2.5, so

M = 2.5r³ ← equation of proportionality

When M = 540, then

540 = 2.5 r³ ( divide both sides by 2.5 )

216 = r³ ( take the cube root of both sides )

r = $\sqrt[3]{216}$ = 6

5 0

3 years ago

Find two unit vectors orthogonal to both 8, 5, 1 and −1, 1, 0 .

Elina [12.6K]

In order to do this, you must first find the "cross product" of these vectors. To do that, we can use several methods. To simplify this first, I suggest you compute:

‹1, -1, 1› × ‹0, 1, 1›

You are interested in vectors orthogonal to the originals, which don't change when you scale them. Using 0,-1,1 is much easier than 6s and 7s.

So what methods are there to compute this? You can review them here (or presumably in your class notes or textbook):
http://en.wikipedia.org/wiki/Cross_produ...

In addition to these methods, sometimes I like to set up:
‹1, -1, 1› • ‹a, b, c› = 0
‹0, 1, 1› • ‹a, b, c› = 0

That is the dot product, and having these dot products equal zero guarantees orthogonality. You can convert that to:

a - b + c = 0
b + c = 0

This is two equations, three unknowns, so you can solve it with one free parameter:

b = -c
a = c - b = -2c

The computation, regardless of method, yields:
‹1, -1, 1› × ‹0, 1, 1› = ‹-2, -1, 1›

The above method, solving equations, works because you'd just plug in c=1 to obtain this solution. However, it is not a unit vector. There will always be two unit vectors (if you find one, then its negative will be the other of course). To find the unit vector, we need to find the magnitude of our vector:

|| ‹-2, -1, 1› || = √( (-2)² + (-1)² + (1)² ) = √( 4 + 1 + 1 ) = √6

Then we divide that vector by its magnitude to yield one solution:

‹ -2/√6 , -1/√6 , 1/√6 ›

And take the negative for the other:

‹ 2/√6 , 1/√6 , -1/√6 ›

7 0

3 years ago