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2 years ago

Which value is a solution for the equation tan x/2 = -1?

Mathematics

2 answers:

Luba_88 [7]2 years ago

4 0

Answer:

Step-by-step explanation:

What we have to do is to find the arc tan

x/2 = arc tan (-1)

tan is negative on the 4th and second quadrant

arc tan (-1) = 135 or 315

pi is 180 degrees

so we have;

135 is 3 pi/4

multiplied by the 2

= 6 pi/4 which is 3 pi/2

315 is 7 pi/4 which is same as 7 pi/2 when we multiply by 2

zysi [14]2 years ago

3 0

Answer:

the answer is d

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Your parents ask you to choose between two offers for an allowance. The first offer is to receive one penny on the first day, 2

Ahat [919]

Answer:

pennies/first offer

Step-by-step explanation:

you would be rich

1x2=2 2^364= a lot of pennies

5 0

3 years ago

Read 2 more answers

How much wrapping paper did he use ,in square inches

Paul [167]

Answer:

96.76 square inches

Step-by-step explanation:

5.2x5.2=27.04

6.7x5.2/2=17.42

17.42x4=69.68

69.68+27.04=96.76

Hope this helps <3 Comment if you want more thanks and be sure to give brainliest (4 left) <3

6 0

2 years ago

In a scale drawing, a building has a length of 15 cm. The actual length of the building is 37.5 feet. Whats the scale of the dra

Feliz [49]

Answer:

$\frac{15}{37.5}\ \frac{cm}{ft}$

$1.31:100$

Step-by-step explanation:

we know that

The scale of the drawing is equal to divide the length of a building in the scale drawing by the actual length of a building

$\frac{15}{37.5}\ \frac{cm}{ft}$

That means

15 cm in the drawing represent 37.5 ft in the actual

Remember that

$1\ ft=30.48\ cm$

Convert 15 cm to ft

divide by 30.48

$15\ cm=15/30.48\ ft$

substitute

$\frac{15}{37.5}\ \frac{cm}{ft}=\frac{(15/30.48)}{37.5}=\frac{0.0131}{1}$

$1.31:100$

That means

1.31 units in the drawing represent 100 units in the actual

5 0

3 years ago

Perform the indicated operation. 9z^3/16xy . 4x/27z^3

ziro4ka [17]

Answer:

$\frac{1}{12y}$

Step-by-step explanation:

This is a multiplication problem.

We want to multiply $\frac{9z^3}{16xy}\cdot \frac{4x}{27z^3}$

We factor to get:

$\frac{9z^3}{4\times 4xy}\cdot \frac{4x}{9\times 3z^3}$

We now cancel out the common factors to get:

$\frac{1}{4\times y}\cdot \frac{1}{1\times 3}$

We now multiply the numerators and the denominators separately to get.

This simplifies to $\frac{1}{12y}$

Therefore the simplified expression is $\frac{1}{12y}$

8 0

3 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

3 years ago