The sequence AAU GGC UAC is composed of three codons each of which codes for a different amino acid.
AAU codes for the amino acid called threonine.
GGC codes for the amino acid called glycine
UAC codes for the amino acid called tyrosine.
So the chain will read threonine-glycine-tyrosine.
There are 64 possible 3 - letter combinations of DNA coding units A, C, G and T. Of these, there are three stop or non- sense codons that do not code for any amino acid, while the remaining 61 code for different amino acids.
Given the situation described in the question, the nurse
should evaluate the child's neurologic status. This is because there are signs
of meningitis (the priority when meningitis is suspected is to evaluate
neurologic status). Standard precautions should be initiated while carrying out
the test if there's the risk of contacting body fluids.
Additional information is missing. It is as follows: In fruit flies, the allele for red eyes is dominant over the allele for pink eyes. Straight wings are dominant over curled wings.
Answer:
Genotype = RrSS and RrSs in 1:1 ratio so each has 0.5 probability
Phenotype = All red eyed and straight winged
Explanation:
Given,
Red eyes (R) is dominant over pink eyes (r)
Straight wings (S) is dominant over curled wings (s)
Fly 1 : Homozygous red eyed, curly winged = RRss
Fly 2 : Pink eyed, heterozygous straight winged = rrSs
RRss will produce Rs gametes and rrSs will produce rS and rs gamates.
When fly 1 and fly 2 mate : RRss X rrSs :
rS rs
RS RrSS RrSs
The genotypic ratio is 1 : 1 ( RrSS : RrSs ) that means that each genotype has 0.5 probability. Both the genotypes though have at least one dominant allele for each gene so the entire progeny will have red eyes and straight wings.
Answer:
The individual is a male. Explanation: In mammals, sex is determined by a pair of sexual chromosomes.
