Are the triangles congruent?? Justify the answer
2 answers:
Answer:
the triangles are congruent
Step-by-step explanation:
method 1: Angle-Angle-Angle congruency test
angle BAC = angle DEC(given)
angle ABC = angle EDC
angle BCA = angle DCE
method 2: Side Angle Side Congruency test
BC = DC (both are 4 cm)
angle BCA = angle DCE (vertically opp. angles, straight lines intersect)
AC = EC (both are 6 cm)
side note:
1. when testing for congruency and giving the different congruency test, always ensure that the sides or angles mentioned are in corresponding order of the congruent triangles.
2. see that from the explanation given i do not anyhow mix up the sides with any sides or mess up points with any points(will show drawing of an example of what i mean)
pls dont mind the ugly handwriting as well since i dont have a stylus
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Answer:
Step-by-step explanation:
We have the following expression:
We can find the GCF with the following steps.
1. Find the GCF for the numerical part 15 and -21
The factors for 15 are : 1,3,5,15
The factors for -21 are -21,-7,-3,-1,1,3,7,21
And the common factors are 1,3
The GCF for the numerical part is 3*1 = 3
2. Find the GCF for the variable
The factors of x^2 are : x*x
The factors of x are: x
The common factors are x for this case, so then the GCF for the variable part is x
3. Multiply the two results from steps 1 and 2
GCf= 3*x = 3x
If we consider the new expression:
We can find the GCF with the following steps.
1. Find the GCF for the numerical part 15 and -21
The factors for 15 are : 1,3,5,15
The factors for -21 are 1,3,7,21
And the common factors are 1,3
The GCF for the numerical part is 3*1 = 3
2. Find the GCF for the variable
The factors of x^2 are : x*x
The factors of x are: x
The common factors are x for this case, so then the GCF for the variable part is x
3. Multiply the two results from steps 1 and 2
GCf= 3*x = 3x
And as we can see both GCF are equal. So then we satisfy the condition required.
