Answer:
1/7 (option d) of the sensors on the satellite have been upgraded
Step-by-step explanation:
Each unit contains the same number of non-upgraded sensors
number of non-upgraded sensors for each module (nus)
total number of upgraded sensors on the satellite (tus)
satellite is composed of 30 modular units
total number of non-upgraded sensors on the satellite (tnus):
tnus=30*nus
total number of sensors on the satellite (ts):
ts=tnus+tus = 30*nus + tus (I)
The number of non-upgraded sensors on one unit is 1/5 the total number of upgraded sensors on the entire satellite
nus=(1/5)*tus
tus = 5 * nus (II)
Fraction of the sensors on the satellite have been upgraded (FU):
FU = tus/ts
Using I and II
FU= (5* nus)/(30*nus + tus)
FU = (5* nus)/(30*nus + 5 * nus)
FU = (5* nus)/(35*nus)
FU = 1/7
1/7 (option d) of the sensors on the satellite have been upgraded
Answer:
a = 2 5/8
Step-by-step explanation:
14a - (2a + 9) = 3 (12a - 18)
14a - 2a + 9 = 36a - 54
12a + 9 = 36a - 54
12a - 36a = -54 - 9
-24a = -63
a = -63/-24
a = 21/8
a = 2 5/8
Answer:
62.8
Step-by-step explanation:
Using the circumference formula (πd) we can see that the answer is 20π, or 62.8
Yes I agree with that because you combined the terms in the monomial correctly and the degree of the monomial was greater then the degree of any other mono/binomials in the polynomial
