Answer:
Number of fragments is 3
Explanation:
The maximum size of data field in each fragment = 4468 - 20(IP Header)
= 4448 bytes
Hence, the number of required fragment = (10000 - 20)/4448
= 3
Fragment 1
Id = 218
offset = 0
total length = 4468 bytes
flag = 1
Fragment 2
Id = 218
offset = 556
total length = 4468 bytes
flag = 1
Fragment 3
Id = 218
offset = 1112
total length = 1144 bytes
flag = 0
A bar graph is a great graphical representation of disributiation of data
Answer:
168 (although the =< must be corrected to <=)
Explanation:
int count = 0;
for (int row = 4; row <= 15; row++)
for (int col = 0; col < 13; col = col +2)
count+=2;
The inner for loop runs 7 times (for col = 0,2,4,6,8,10,12). Anything higher is not less than 13. Therefore the inner loop increments count by 2 seven times, i.e. it increments count by 14.
The outer for loop runs 12 times (for row = 4,5,6,7,8,9,10,11,12,13,14,15).
If the count is incremented by 14 twelve times, you are incrementing it by 14*12 = 168.
Therefore the count goes from 0 to 168 after the nested loops.
Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
