Answer:
63
Step-by-step explanation:
10 × 3 = 30
3× 11 = 33
30 + 33 = 63
Solve for x:
x^2 + 4 x + 25 = 0 I ssume that's the notation.
Subtract 25 from both sides:
x^2 + 4 x = -25
Add 4 to both sides:
x^2 + 4 x + 4 = -21
Write the left hand side as a square:
(x + 2)^2 = -21
Take the square root of both sides:
x + 2 = i sqrt(21) or x + 2 = -i sqrt(21)
Subtract 2 from both sides:
x = i sqrt(21) - 2 or x + 2 = -i sqrt(21)
Subtract 2 from both sides:
Answer: x = i sqrt(21) - 2 or x = -i sqrt(21) - 2
Answer:
The diameter of the circle O is <em>12 units</em>
Step-by-step explanation:
There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of

and the triangle B0C is right
<u>Relations in the Circle</u>
The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.
Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r
Applying Pythagoras's theorem:

Thus we have




The diameter of the circle O is D=2(6) = 12 units
Opposite
additive inverse
Answer:
z = 8/3
Step-by-step explanation:
10- 3/4z = 8
Subtract 10 from each side
10-10- 3/4z = 8-10
-3/4z = -2
Multiply each side by -4/3
-3/4z * -4/3 = -2 *4/3
z = 8/3