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Anettt [7]
3 years ago
6

HELP If a scientist find an ice core from 30,000 years ago that contains chemicals radically different than the chemicals that a

re around today they would likely conclude that
A- the atmosphere never changes its composition

B- the atmosphere 30,000 years ago was different than our atmosphere today

C- these chemicals are abundant today

D the number of layers they counted was incorrect
Mathematics
1 answer:
Igoryamba3 years ago
5 0
B- the atmosphere 30,000 years ago was different than our atmosphere today
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How do you answer this question.
Ipatiy [6.2K]
Lets write this out:-

\frac{50}{100} + \frac{30}{100}

To answer this we just need to add the numerators of both fractions because the denominator's are already common multiples. 

\frac{50}{100}+ \frac{30}{100} = \frac{80}{100}

Now lets simplify \frac{80}{100}.

\frac{80/20}{100/20}=  \frac{4}{5}

So, \frac{50}{100}+  \frac{30}{100} = \frac{80}{100}= \frac{4}{5}

Hope I helped ya!! xD
8 0
3 years ago
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Vanyuwa [196]
Thanks. I’m not struggling or anything but thanks for the kind words.
7 0
3 years ago
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Your paycheck each week is $500.00. If you want to save $2000 in one year, how much should you set aside from each paycheck?
Mnenie [13.5K]
There are 52 weeks in a year. In order to figure out how much you have to save each week to save a total of $2000, you have to divide $2000 by 52. 

2000÷52= 38.462

So to save $2000 you would have to set aside about $38.50 each week. 
8 0
3 years ago
Rodney is given twi equations:x-y=11 and 2x+y=19
lozanna [386]

Answer:

x= 10 and y= -1

Step-by-step explanation:

Rewrite your second equation Y= -2x+ 19 then plug it into the first equation.

x- (-2x + 19) = 11

x + 2x - 19 =11

3x - 19 = 11

3x = 30

x = 10

The plug that answer into the first equation and solve.

10 - y = 11

-y = 1

y = -1

3 0
3 years ago
The area of the sector of a circle with a radius of 8 centimeters is 125.6 square centimeters. The estimated value of pi is 3.14
tangare [24]
\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta\pi r^2}{360}\qquad 
\begin{cases}
\theta=\textit{angle in degrees}\\
r=radius\\
----------\\
r=8\\
A=125.6
\end{cases}
\\\\\\
360A=\theta\pi r^2\implies \cfrac{360A}{\pi r^2}=\theta\implies \cfrac{360\cdot 125.6}{\pi 8^2}=\theta
4 0
3 years ago
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