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Answer:
Explanation:
Let assume that the missing aqueous solution of 4-chlorobutanoic acid = 0.76 M
Then, the dissociation of 4-chlorobutanoic acid can be expressed as:
⇄
+
The ICE table can be computed as:
⇄
+
Initial 0.76 - -
Change -x +x +x
Equilibrium 0.76 - x x x
where:
however, the value of x is so negligible:
0.76 -x = 0.76
Then:
x = 0.00479 M
∴
0.00479 M
= (0.76 - 0.00479) M
= 0.75521 M
Finally, the percentage of the acid dissociated is;
= ( 0.00479 / 0.76) × 100
= 0.630 M