We know, mole of gas in ideal conditions is 22.414 L
Here, CH4 volume = 8.9L
So, number of moles = 8.9 / 22.414 = 0.397 moles
Here, in balanced equation we have a ratio CH4 : H2O = 1:2.
So, mole so water = , 0.397*2= 0.794 moles
In liters it would be: 0.794 * 22.414 = 17.80 L
In short, Your Answer would be 17.80 Liters
Hope this helps!
It causes an overdose which leads to the liver releasing less Glycose. The level of glucose the insulin is allowing cells to absorb which causes low blood sugar levels. sorry if that's a bit confusing.
Answer:
The answer to your question is: x = 0.185 mol of Al2O3
Explanation:
Data
10 g of Al and 19 grams of O2
Reaction: 4Al + 3O2 → 2Al2O3
4(27) 3(32) 2 ( 102)
108g 96g 204g
Limiting reactant
108g Al ------------------ 96g O2
10 g ----------------- x
x = (10 x 96) / 108 = 8.9 g of O2
Then limiting reactant is Al
So
108 g of Al ---------------------- 204 g of Al2O3
10 g ---------------------- x
x = (10 x 204) / 108 = 18.8 g of Al2O3
102 g of Al2O3 ----------------- 1 mol
18.8 ----------------- x
x = 0.185 mol of Al2O3
I think it is the first choice
Hope that helped!
