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finlep [7]
3 years ago
10

What is the messure of N and the two angles; an-16 and 6n

Mathematics
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

14, 96,84

Step-by-step explanation:

8n  - 16 + 6n = 180 {Supplementary angles}

<u>8n + 6n</u>  -16 = 180

Combine like terms

14n - 16 = 180

Add 16 to both sides

14n = 180 + 16

14n = 196

Divide both sides by 14

n = 196/14

n = 14

8n - 16 = 8*14 - 16 = 112 - 16 = 96

6n = 6 *14 = 84

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there are 5 in each row


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3 years ago
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2x-5/5 +x-2=3(x+5). Find the value of x?
deff fn [24]

Answer:

Step-by-step explanation:

\frac{2x - 5}{5} + x - 2 = 3(x + 5)

\frac{2x - 5}{5} + x - 2 = 3x + 15

\frac{2x - 5}{5} = 2x + 17

2x - 5 = 10x + 85

-8x = 90

x = \frac{-45}{4}

5 0
3 years ago
When 3 + 3x - 5 - 8x is simplified, the result is:
nasty-shy [4]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
Which equation has the same solution as this equation?
lesya [120]

Answer:

3rd Option is correct.

Step-by-step explanation:

Given Equation:

x² - 16x + 12 = 0

First We need to find solution of the given equation.

x² - 16x + 12 = 0

here, a = 1   , b = -16  &  c = 12

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-16)\pm\sqrt{(-16)^2-4(12)}}{2}

x=\frac{16\pm\sqrt{256-48}}{2}

x=\frac{16\pm\sqrt{208}}{2}

x=\frac{16\pm4\sqrt{13}}{2}

x=8+2\sqrt{13}\:\:andx=8-2\sqrt{13}

Now,

Option 1).

( x - 8 )² = 144

x - 8 = ±√144

x - 8 = ±12

x = 8 + 12 = 20   and x = 8 - 12 = -4

Thus, This is not correct Option.

Option 2).

( x - 4 )² = 4

x - 4 = ±√4

x - 4 = ±2

x = 4 + 2 = 6   and x = 4 - 2 = 2

Thus, This is not correct Option.

Option 3).

( x - 8 )² = 52

x - 8 = ±√52

x - 8 = ±2√13

x  = 8 + 2√13   and x = 8 - 2√13

Thus, This is correct Option.

Option 4).

( x - 4 )² = 16

x - 4 = ±√116

x - 4 = ±4

x = 4 + 4 = 8  and x = 4 - 4 = 0

Thus, This is not correct Option.

Therefore, 3rd Option is correct.

8 0
3 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
4 years ago
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