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Juli2301 [7.4K]
3 years ago
9

When would you want to have a quadratic function in standard form ?

Mathematics
1 answer:
zepelin [54]3 years ago
4 0

Answer:

hay I'm sorry that I can't give you the answer but is it okay that we talk as friends

You might be interested in
Determine the best method to solve the system of equations. Then solve the system.
maxonik [38]

Answer:

x=1  y = -1/2

(1,-1/2)

Step-by-step explanation:

7x-2y=8  

5x+2y=4

I would use elimination since we have 2y in one equation and -2y in the other

7x-2y=8  

5x+2y=4

--------------------

12x = 12

Divide each side by 12

12x/12 = 12/12

x =1

The substitute back into equation 2

5(1) +2y = 4

5 +2y = 4

Subtract 5

5-5+2y = 4-5

2y = -1

Divide by 2

2y/2 = -1/2

y = -1/2

8 0
4 years ago
Read 2 more answers
If z varies directly as x and z=30 when x=8 find z when x=4
dangina [55]
Z=kx, 30=8k, so k=30/8=15/4 and z=15x/4, so when x=4, z=15.
8 0
3 years ago
I need the answer for 90 please its due tommorow!
babunello [35]
Jacqueline is incorrect. 
To find how much trash you can clean in 4 days if you already know how much trash you can clean in one day, multiply 1 2/3 (how much you can clean in one day) by 4. 
Another way to write 1 and 2/3 miles is 5/3 (converting a mixed number to a single fraction). Then, 5/3 x 4 = 20/3. (To multiply fractions, just multiply across, leaving 5 x 4 in the numerator and 4 x 1 in the denominator.)
Jacqueline said you would be able to clean 19/3 miles but you can actually clean 20/3.
4 0
3 years ago
Read 2 more answers
Find the remainder when f(x) = x^3 + 14x^2 − 7x − 10 is divided by x − 3.
Elanso [62]

Answer:

122

Step-by-step explanation:

(3)³ + 14(3²) - 7(3) - 10

122

Used remainder theorem

6 0
3 years ago
A.
Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

f(x) = x^{2} + 3x - 1

So

a = 1, b = 3, c = -1

\bigtriangleup = 3^{2} - 4*1*(-1) = 13

x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3

x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0
3 years ago
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