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ivann1987 [24]
2 years ago
7

James says,

Mathematics
2 answers:
Dima020 [189]2 years ago
6 0

-3^3 = -27

Step-by-step explanation:

Thats because -3^3 is (-3×3×3) not (-3×-3×-3) which we are multiplying a the constant not the the powers

Alborosie2 years ago
6 0

Jamie is right because when you cube a number, you multiply it by itself three times. And we know that when 3 negative numbers are multiplied are product will be negative.

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Simplify
melomori [17]

Answer: 4\sqrt{3}

Step-by-step explanation:

For this exercise it is important to remember the following:

i=\sqrt{-1} \\\\i^2=-1

Given the following expression:

-2i\sqrt{-12}

You can notice that the radicand (the number inside the square root) is negative. Therefore, in order to simplify the expression, you need to follow these steps:

1. Replace \sqrt{-1} with i and simplify:

(-2i)(i)\sqrt{12}=-2i^2\sqrt{12}=-2(-1)\sqrt{12}=2\sqrt{12}

2. Descompose 12 into its prime factors:

12=2*2*3=2^2*3

3. Substitute into the expression:

=2\sqrt{2^2*3}

4. Since \sqrt[n]{a^n}=a, you can simplify it:

=(2)(2)\sqrt{3}=4\sqrt{3}

4 0
2 years ago
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Nostrana [21]
C is the ryt answer ......
3 0
3 years ago
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soldier1979 [14.2K]
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Is RATIONAL , IRRATIONAL,NON REAL NUMBERS <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B27" id="TexFormula1" title=" \sqrt{
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Answer:

It's irrational

Step-by-step explanation:

the square root of 27 is equal to:

\sqrt{27} = \sqrt{3\cdot3\cdot3} = 3\sqrt{3}

We know that \sqrt{3} is an irrational number (but a real number), so 3\sqrt{3} is the same.

In case we need to prove that \sqrt{3} is irrational, please leave a comment.

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Step-by-step explanation:

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