What is the area of this trapezoid?
1 answer:
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Answer:
The value of a = 8 and b= 2 for PQRS to be a parallelogram
Step-by-step explanation:
Given as :
Quadrilateral PQRS having side PQ , QR , RS , PS
The measure of side is
PQ = 6b , QR = 4a + 1
RS = 11b - 10 , PS = 2a + 9
The measure of angle PQR is (6x + 13) And PSR is (7x - 5)
The parallelogram become quadrilateral when its opposite sides is parallel and equal
I.e PQ = RS And QR = PS
Or 6b = (11b - 10)
Or, 10 = 11b - 6b
Or, 5b = 10
∴ b= = 2 or, b = 2
Again ∵ QR = PS
So, 4a + 1 = 2a + 9
Or, 4a - 2a = 9 - 1
∴ a = 8
Hence the value of a = 8 and b= 2 for PQRS to be a parallelogram Answer