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2 years ago

Explain the difference between squaring a number and square roots.

Mathematics

1 answer:

Elena L [17]2 years ago

3 0

Answer:

mews jh

Step-by-step explanation:

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Given AE = EC, for what value of x is quadrilateral ABCD a parallelogram?

34kurt

Answer:

Each side of the Rhombus is equal to 4x

6 0

2 years ago

Roman numeral xxiii

Elden [556K]

X= 10

I= 1

10+10+1+1+1= 23

I hope this helps!

3 0

3 years ago

Read 2 more answers

[21] Please help. What is the volume of the cooler in cubic inches?

GenaCL600 [577]

Answer:

3,724

Step-by-step explanation: Length x width x height

19 x 14 x 14

19 x 14 = 266

266 x 14 = 3,742

hope this helped :)

6 0

2 years ago

For the function f (x) = 3 (x + 7), find -1().

AlekseyPX

Given:

The function is $f(x)=3(x+7)^{\frac{1}{4}}$ .

To find:

The function $f^{-1}(x)$ .

Solution:

We have,

$f(x)=3(x+7)^{\frac{1}{4}}$

Substitute f(x)=y.

$y=3(x+7)^{\frac{1}{4}}$

Interchange x and y.

$x=3(y+7)^{\frac{1}{4}}$

Divide both sides by 3.

$\dfrac{x}{3}=(y+7)^{\frac{1}{4}}$

Taking power 4 on both sides.

$\left(\dfrac{x}{3}\right)^4=y+7$

Subtract 7 from both sides.

$\left(\dfrac{x}{3}\right)^4-7=y$

$y=\left(\dfrac{x}{3}\right)^4-7$

Substitute $y=f^{-1}(x)$ .

$f^{-1}(x)=\left(\dfrac{x}{3}\right)^4-7$

Therefore, the correct option is C.

5 0

2 years ago

A square pyramid has a base with an area of 20 square meters, and its lateral faces have a slant height of x meters. Sydney is c

svetoff [14.1K]

1. Consider the pyramid ABCDE in the figure 1 attached:

Each side of the square base equals $\sqrt{20} = \sqrt{4*5} = \sqrt{4}* \sqrt{5}=2 \sqrt{5}$ (units)

Area of 1 lateral side of pyramid ABCDE is $\frac{1}{2}* 2 \sqrt{5}*x=\sqrt{5}x$

so the total lateral area is $4\sqrt{5}x$ (units squared)

and the total surface area is $20+4\sqrt{5}x$ (units squared)

2. Now consider the second figure KLMNP, Sydney's pyramid:

The lateral area is $4* \frac{1}{2}* 4 \sqrt{5} *2x=16 \sqrt{5}x$

so the total area of the second pyramid is $20+16 \sqrt{5}x$

So 2 things can be said about the areas:

i) the lateral area of Sydney's pyramid is $\frac{16 \sqrt{5}x}{4\sqrt{5}x} =4$ times larger than the lateral area of the original pyramid.

ii) The total area of Sydney's pyramid is $(20+16 \sqrt{5}x)-(20+4\sqrt{5}x)=12\sqrt{5}x$ units squared larger than the total area of the original pyramid.

5 0

3 years ago

Read 2 more answers