Question

3. Find the coordinates of the midpoint of Asif A(-4, 7) and S(5,3). number 9 please

Answer 1

Step-by-step explanation:

slope = (x1 + x2/2 , y1 + y2/2)

x1 = -4

x2 = 5

y1 = 7

y2 = 3

after inserting the values we got,

→ ( -4 + 5/2 , 7+3/2 )

→ ( 1/2 , 10/2 )

→ ( 0.5 , 5 )

hope this answer helps you dear...take care mau u have a great day ahead!...

Answer 2

Answer:

( $\frac{1}{2}$, 5 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

Here (x₁, y₁ ) = A (- 4, 7) and (x₂, y₂ ) = B (5, 3 ) , then

midpoint = ( $\frac{-4+5}{2}$ , $\frac{7+3}{2}$ ) = ($\frac{1}{2}$ , $\frac{10}{2}$ ) = ($\frac{1}{2}$ , 5 )