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Montano1993 [528]
3 years ago
7

Please help with this fast

Mathematics
1 answer:
vitfil [10]3 years ago
3 0

Answer:

repost it, I cant see all of the question

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3 years ago
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2 years ago
Given the following definition, compute Q(5). Q(n) = 0 if n = 0 2 if n = 1 4 if n = 2 Q(n − 1) + Q(n − 2) + Q(n − 3) if n > 2
aalyn [17]
We have 
Q(0)=0\\
Q(1)=2\\
Q(2)=4
and Q(n)=Q(n-1)+Q(n-2)+Q(n-3)\mbox{ when } n\ \textgreater \ 2.
So 
Q(3)=Q(2)+Q(1)+Q(0)=4+2+0=6\\
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Q(5)=Q(4)+Q(3)+Q(2)=12+6+4=22.

3 0
2 years ago
827 divided by 1120
KiRa [710]

It can be the last one, 827 over 1120

Hope that helps

4 0
3 years ago
Read 2 more answers
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