What is the maximum y-value for f(x)= -4(x-6)^2 + 3
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Answer:
For the column "Slope Intercept", the graph is displaying y = -7/2x + 3. Because the line is going down 7 units and to the right 2 units, and the 3 is the point in which the line crosses the y-axis.
For the "Standard" column, it will be
7x + 2y = 6, because that's what it would look like in standard form. (To turn it from standard to slope intercept form, remember you must first subtract 7x on both sides to get 2y = -7x + 6, and then divide by 2 on both sides to get
y = -7/2x + 3.)
For column "Point Slope", I just realized you are supposed to pick a point on the line and plug the coordinates into this formula:⤵⤵⤵
<em>This is the point-slope formula.⤵⤵⤵</em>
For example we'll use point (2,-4). Also, remember that coordinates are written as (x,y), and that m represents slope.
So we have: y - (-4) = -7/2(x-2).
In other words, "Point Slope" would be
y + 4 = -7/2(x-2).
By the way, sorry this is a bit long, and took a while to complete. I had to re-educate myself on point-slope. Anyways hope this helps, I tried :)