3 years ago

What is the maximum y-value for f(x)= -4(x-6)^2 + 3

Mathematics

1 answer:

vaieri [72.5K]3 years ago

3 0

I think the answer is -4x^2+48x-141. Please double check my work.

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Vanessa was baking cookies. Each batch of cookies made 3 dozen. If Vanessa uses 6 cups of flour total and each batch requires 1

erastovalidia [21]

Each batch gives you 3 dozen and you need 1 1/2 cups for each batch of cookies

she uses 6 cups in total, so divide 6 by 1 1/2 to get the number of batches

6 ÷ 1 1/2 = 4 batches

so 4 batches × 3 dozen cookies = 12 dozen cookies

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3 years ago

Find the price of a $50 item after a 20% discount

il63 [147K]

20% = 0.20
50 * 0.20 = $10 discount
50 - 10 = 40

The price after 20% discount is $40

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3 years ago

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Can someone help me please

Damm [24]

Answer:

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Step-by-step explanation:

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3 years ago

Which expression is equivalent to 6(a-3)?<br> 18a<br> 6(a)-6(3)<br> 6(a)-3<br> 3a

arsen [322]

Answer:

Option 2

Step-by-step explanation:

6(a)-6(3)=6a-6×3=6(a-3)

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3 years ago

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Evaluate tan45/sin30 . In your final answer, include all calculations.

Maslowich

From the identity $\displaystyle{ \tan x= \frac{\sin x}{\cos x}$ , and from the values:

$\sin45^{\circ}=\cos45^{\circ}= \frac{ \sqrt{2}}{2}$ ,

we have: $\displaystyle{ \tan 45^{\circ}= \frac{\sin 45^{\circ}}{\cos 45^{\circ}}= \frac{ \frac{ \sqrt{2}}{2}}{\frac{ \sqrt{2}}{2}} =1$ .

We also know that $\sin30^{\circ}= \frac{1}{2}$ .

Thus, $\displaystyle{ \frac{\tan 45^{\circ}}{\sin30^{\circ}} = \frac{1}{\frac{1}{2}}=2.$

Answer: 2

8 0

3 years ago