Answer:
210, 211, 212
Step-by-step explanation:
If we denote the first number as x, then the second number can be written as x + 1 and the third number as x + 2.
The equation is:
x + (x + 1) + (x + 2) = 633
3x + 3 = 633
3x = 633 - 3
3x = 630
x = 210
So the three consecutive numbers we're looking for are: 210, 211, 212
19. No
20. No
21. Yes
23. 1.8 miles
<span>We have to use PEMDAS for this expression.
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
</span>(2x^2 - 5x + 4) Original Mathematical Expression
[2(7)^2 - 5(7) + 4] Plugging the value of x, 7 into expression.
There are parentheses, so that means we have to work in them.
There are exponents, so we have to do those first.
[2(49) - 5(7) +4] Exponents.
There is multiplication, that we can do, so we do that left to right.
[98 - 35 + 4] Multiplication.
There is no division.
There is addition and subtraction, so we do those left to right.
[63 + 4] Subtraction.
67 Addition.
Final Answer: 67
Answer:
(5,4) is the solution
Step-by-step explanation:
2x + y = 14 --> y = -2x + 14
Substitute y = -2x + 14 into 3x - 2y = 7
3x - 2( -2x + 14) = 7
3x + 4x - 28 = 7
7x = 35
x = 5
y = -2(5) + 14
y = -10 + 14
y = 4
Answer (5 , 4)
