Answer:
Janies' monthly pocket money is $180.
Step-by-step explanation:
Janies' adjusted monthly pocket money:
Initial pocket money = $150
Ratio of new pocket money = 6:5
Let his new pocket money be represented by x,
x:$150 = 6:5
$150 x 6 = x (5)
$900 = 5x
x = 
x = $180
Therefore, Janies' monthly pocket money is $180.
 
        
             
        
        
        
Answer:
9
Step-by-step explanation:
The mode is the number that occurs most often. The number nine occurs 4 times.
 
        
                    
             
        
        
        
Let us bear in mind the equivalent value of these coins: 
One dime = $0.10 
One quarter = $0.25 
Let x = number of dimes 
        y<span> = number of quarters</span> 
Since the boy has 70 coins in total, we can say that: 
<span>x + y = </span><span>70 </span>(can be written as x = 70 – y) 
Since the boy has a total of $12.40, we can say that: 
0.10x + 0.25y = 12.40 
To solve this problem, we need to solve this system of equation. We have to substitute the value of x as written in the first equation (x = 70 –y) 
0.10(70 – y) + 0.25y = 12.40 
7 – 0.10y + 0.25y = 12.40 
0.15y = 5.40 
y = 36 
X = 70 – 36 
X = 34 
Therefore,<span> the boys </span>has<span> 34 dimes and 36 quarters. To check our answer, we just have to check if his money would total $12.40.</span> 
34 dimes = $3.40 
36 dimes = $9.00 
<span>Total           </span><span>$12.40</span>
 
        
                    
             
        
        
        
To find angle c, the fourmula is 1/2 of the intercepted arc. so, this would be (-3x-6)=(-4x)/2, then bring the 2 over, (-3x-6)2=-4x, multiply the 2, -6x-12=-4x, -2x=12, simplify, x=-6
check by plugging in.
        
                    
             
        
        
        
Answer:
slope intercept form is : y = mx + b
where m is the slope and b is the y-intercept.
The slope, m = (y' - y)/(x' - x)
Is found using the two pints.
The apostrophe is used to denote the other point, different from point (x,y).
once you have the slope, m for the equation y = mx + b ; use one of the points as (x,y) to solve for b.