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kherson [118]
3 years ago
7

Enter the factor under the radical

ula1" title="(a - b) \sqrt{a - b} " alt="(a - b) \sqrt{a - b} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
kvasek [131]3 years ago
3 0

\\ \rm\longmapsto (a-b)\sqrt{a-b}

\\ \rm\longmapsto (a-b)(a-b)^{\frac{1}{2}}

\\ \rm\longmapsto (a-b)^{1+\dfrac{1}{2}}

\\ \rm\longmapsto (a-b)^{\dfrac{3}{2}}

irga5000 [103]3 years ago
3 0

Answer:

\dashrightarrow \: { \tt{(a - b) \sqrt{a - b} }} \\  \\ \dashrightarrow \: { \tt{ {(a - b)}^{1}  {(a - b)}^{ \frac{1}{2} } }}

• from law of indices:

{ \boxed{ \rm{ ({x}^{n} )(  {x}^{m} ) =  {x}^{(n + m)} }}}

therefore:

\dashrightarrow \: { \tt{ {(a - b)}^{(1 +  \frac{1}{2} )} }} \\  \\ \dashrightarrow \: { \tt{ {(a - b)}^{ \frac{3}{2} } }}

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alexira [117]
Area=basexheight

Area=9x4

Area=36
4 0
3 years ago
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Help me Please! Find the volume and surface area for all.
HACTEHA [7]

Answer:

V =41.41³

A = 94.41²

----

V =225.16³

SA =283.25²

----

V = 64³

SA =113.32²

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V =433.33³

SA = 378.57²

Step-by-step explanation:

Picture 2 = a = 1/2 base = 3.5 x 3.5 = 12.25  b= 5 x 5 = 25

c²= a² + b² = 3.5² + 5²

c ²= √12.25 + √25

c ²= √ 37.5 = 6.12372435696

c ² = 6.1237   missing side

Picture 1 + 2  formula SA = bh + (s1 + s2 + s3)H

V =  V= 1/2 b x h  h x SA

Picture 3 + 4  formula SA= a²+ 2a   a² / 4 + h²    V= a²  h/3

5 0
3 years ago
Write 8.6 x 10^-9 in Standard Form <br><br> Please help :)
Marysya12 [62]

Answer:

8.6 × 10-9

Step-by-step explanation:

8 0
2 years ago
(-18x^2+12x-2)*(x^3+12x^2+48x+64)
prohojiy [21]
<h2>Answer:</h2>

-18x^5-204x^4-722x^3-600x^2+672x-128

<h2>Explanation:</h2>

( - 18 {x}^{2}  + 12x - 2)

( {x}^{3}  + 12 {x}^{2}  + 48x + 64)

There are multiple ways to solve this for example the foil method or the box method. I prefer to do the box method.

First we are going to set it up

After we set it up we have to solve it so first we are going to multiply

{x}^{3}  \times  - 18 {x}^{2}  =  - 18 {x}^{5}

We have to add the exponent

- 18 {x}^{2}  \times 12 {x}^{2}  =  - 216 {x}^{4}

- 18 {x}^{2}  \times 48x =  - 864 {x}^{3 }  \\  - 18{x}^{2}  \times 64 =  - 1152 {x}^{2}  \\ 12x \times  {x}^{3}  = 12 {x}^{4}  \\ 12x \times 12 {x}^{2}  = 144 {x}^{3}

12x \times 48x = 576 {x}^{2}  \\ 12x \times 64 = 768x

- 2  \times  {x}^{3}  =  - 2 {x}^{3}  \\  - 2 \times 12 {x}^{2}  =  - 24 {x}^{2}  \\  - 2 \times 48x =  - 96x \\  - 2 \times 64 =  - 128

Now we have to add them

-18x^5 stays because there is nothing to add to

Now we add the rest

-216 {x}^{4}  + 12 {x}^{4}  =  - 204 {x}^{4}

- 864 {x}^{3}  + 144 {x}^{3}  +  - 2 {x}^{3}  = -  722 {x}^{3}

768x - 96x = 672x

And -128 stays the same

- 1152 {x}^{2}  + 576 {x}^{2}  - 24 {x}^{2}  =  - 600 {x}^{2}

The answer is

-18x^5-204x^4-722x^3-600x^2+672x-128

5 0
4 years ago
A set of elementary school student heights are normally distributed with a mean of 105105105 centimeters and a standard deviatio
steposvetlana [31]

Answer:

The proportion of student heights that are between 94.5 and 115.5 is 86.64%

Step-by-step explanation:

We have a mean \mu = 105 and a standard deviation \sigma = 7. For a value x we compute the z-score as (x-\mu)/\sigma, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%

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4 years ago
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