Answer:
a) 3⁵5³.
b) 1
c) 23³
d) 41·43·53
e) 1
f) 1111
Step-by-step explanation:
The greatest common divisor of two integers is the product of their common powers of primes with greatest exponent.
For example, to find gcd of 2⁵3⁴5⁸ and 3⁶5²7⁹ we first identify the common powers of primes, these are powers of 3 and powers of 5. The greatest power of 3 that divides both integers is 3⁴ and the greatest power if 5 that divides both integers is 5², then the gcd is 3⁴5².
a) The greatest common prime powers of 3⁷5³7³ and 2²3⁵5⁹ are 3⁵ and 5³ so their gcd is 3⁵5³.
b) 11·13·17 and 2⁹3⁷5⁵7³ have no common prime powers so their gcd is 1
c) The only greatest common power of 23³ and 23⁷ is 23³, so 23³ is the gcd.
d) The numbers 41·43·53 and 41·43·53 are equal. They both divide themselves (and the greatest divisor of a positive integer is itself) then the gcd is 41·43·53
e) 3³5⁷ and 2²7² have no common prime divisors, so their gcd is 1.
f) 0 is divisible by any integer, in particular, 1111 divides 0 (1111·0=0). Then 1111 is the gcd
Answer:9 more cups
Step-by-step explanation:
if you subtracts 3 from 12 you get 9 and since you have the same denominator you will keep it the same number
Answer:
Step-by-step explanation:
Yes... G=5 okay....
where is equation list??
Answer:
The rectangular prism has the greatest surface area
Step-by-step explanation:
Verify the surface area of each container
case A) A cone
The surface area of a cone is equal to
we have
----> the radius is half the diameter
substitute the values
case B) A cylinder
The surface area of a cylinder is equal to
we have
----> the radius is half the diameter
substitute the values
case C) A square pyramid
The surface area of a square pyramid is equal to
![SA=b^{2} +4[\frac{1}{2}bh]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7Dbh%5D)
we have
----> the length side of the square
----> the height of the triangular face
substitute the values
![SA=6^{2} +4[\frac{1}{2}(6)(10)]=156\ in^{2}](https://tex.z-dn.net/?f=SA%3D6%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%286%29%2810%29%5D%3D156%5C%20in%5E%7B2%7D)
case D) A rectangular prism
The surface area of a rectangular prism is equal to
![SA=2b^{2} +4[bh]](https://tex.z-dn.net/?f=SA%3D2b%5E%7B2%7D%20%2B4%5Bbh%5D)
we have
----> the length side of the square base
----> the height of the rectangular face
substitute the values
![SA=2(6)^{2} +4[(6)(10)]=312\ in^{2}](https://tex.z-dn.net/?f=SA%3D2%286%29%5E%7B2%7D%20%2B4%5B%286%29%2810%29%5D%3D312%5C%20in%5E%7B2%7D)
Answer:
<h2>a answer ko </h2>
Step-by-step explanation:
<h2>ur welcome. carry on learning </h2>
