Answer:
13 and 25
Step-by-step explanation:
um so dont hold me to this, but if he's twelve years older than susan she would've been twelve and he would've been 24 last year.
Answer:
guessing its Still Runnin
Step-by-step explanation:
Answer:
As there are no options given in the question, but the options in the complete question are;
a) 2/10b) 20%c) 0.02d) 0.2
So, from the given options "c" is not a way to express this.
we can write 20/100 as 2/10 so option a is a way to express given relationship. and if we look at option b, it is also a way to express 20 from 100 is 20%. And if we divide, we get 20/100 = 2/10 = 0.2, so d is also a way to express given relationship. Thus, c is the answer.
Step-by-step explanation:As there are no options given in the question, but the options in the complete question are;
a) 2/10b) 20%c) 0.02d) 0.2
So, from the given options "c" is not a way to express this.
we can write 20/100 as 2/10 so option a is a way to express given relationship. and if we look at option b, it is also a way to express 20 from 100 is 20%. And if we divide, we get 20/100 = 2/10 = 0.2, so d is also a way to express given relationship. Thus, c is the answer.
Answer:
a) the common difference is 20
b) 
c) the common difference is -13
d) 
Step-by-step explanation:
a) what is the common difference of the sequence xn
Looking at the table, we get x_3=16, x_4=36 and x_5= 56
Deterring the common difference by subtracting x_4 from x_3 we get
36-16 =20
So, the common difference is 20
b) what is x_8? what is x_12
The formula used is: 
We know common difference d= 20, we need to find 
Using 
we can find
So, We have 
Now finding 
So, 
Now finding 
So, 
c) what is the common difference of the sequence 
Looking at the table, we get a_7=104, a_8=91 and a_9= 78
Deterring the common difference by subtracting a_7 from a_8 we get
91-104 =-13
So, the common difference is -13
d) what is a_12? what is a_15?
The formula used is: 
We know common difference d= -13, we need to find 
Using 
we can find
So, We have 
Now finding 
, put n=12
So, 
Now finding 
, put n=15
So, 
The range is the set of all valid
y
y
values. Use the graph to find the range.
Interval Notation:
(
−
∞
,
∞
)
