Answer:
1-6 you need to write the JHI DEF where the radius center point is in the middle of each shape next to 1-6 some have 2 shapes so use 6 letters there.
Step-by-step explanation:
1. Area = 72 of 360 = 20% of 716.3 = 143.26inch*2 =JHI
2.Area = 19 of 360 = 68.4% of 69.4 = 47.46km^2 =DEF
3. Area = 92 of 360 = 25.56% of 153.9 = 39.33cm^2
4. Area = 226 of 360 = 64.57% of 706.9 = 456.45ft^2
5. Area = 74 of 360 = 20.55% of 153.9 =31.63 inch^2
6. Area = 326 of 360 = 90.56% of 1452 -137.07 = 1314.93m^2
Answer = $213.72
Net pay = $213.72 (Rounded off to 2 decimal points)
Answer:
105km
Step-by-step explanation:
2.5/15=17.5/x (set up as a proportion)
2.5x=262.5 (cross multiply)
x=105 (Divide)
Let
C-------> the length of a circumference
C=2*pi*r-----> equation 1
we know that
in this problem-----> <span>the circumference of the foundation is 4 times the radius, increased by 114 ft
</span>so
C=4*r+114------> equation 2
(1)=(2)
2*pi*r=4*r+114------> 2*pi*r-4*r=114-----> r*[2*pi-4]=114---> r=114/[2*pi-4]
r=114/[2*pi-4]-----> 50 ft
the answer is
r=50 ft
