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babunello [35]
3 years ago
11

Simplify. 9x^8-18x^6

Mathematics
1 answer:
GrogVix [38]3 years ago
7 0
You cannot simplify this but you can factorise it:

9x^6 (x^2 - 2)
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C

Step-by-step explanation:

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Suppose ABC added a new point, D. If the coordinates of D were (5, 2), what would be the coordinates of D' have to be if it foll
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C the coordinates are just fliped since It was flipped on the y- axis

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2 years ago
Read 2 more answers
What is 42-27x5 what is the answer
bulgar [2K]

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-363

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3 years ago
100 Points!
tester [92]

Part A: x = -5/4, 3 || (-5/4, 0) (3, 0)

To find the x-intercepts, we need to know where y is equal to 0. So, we will set the function equal to 0 and solve for x.

4x^2 - 7x - 15 = 0

4 x 15 = 60 || -12 x 5 = 60 || -12 + 5 = -7

4x^2 - 12x + 5x - 15 = 0

4x(x - 3) + 5(x - 3) = 0

(4x + 5)(x - 3) = 0

4x + 5 = 0

x = -5/4

x - 3 = 0

x = 3

Part B: minimum, (7/8, -289/16)

The vertex of the graph will be a minimum. This is because the parabola is positive, meaning that it opens to the top.

To find the coordinates of the parabola, we start with the x-coordinate. The x-coordinate can be found using the equation -b/2a.

b = -7

a = 4

x = -(-7) / 2(4) = 7/8

Now that we know the x-value, we can plug it into the function and solve for the y-value.

y = 4(7/8)^2 - 7(7/8) - 15

y = 4(49/64) - 49/8 - 15

y = 196/64 - 392/64 - 960/64

y = -1156/64 = -289/16 = -18 1/16

Part C:

First, start by graphing the vertex. Then, use the x-intercepts and graph those. At this point we should have three points in a sort of triangle shape. If we did it right, each of the x-values will be an equal distance from the vertex. After we have those points graphed, it is time to draw in the parabola. Knowing that the parabola is positive, we draw in a U shape that passes through each of the three points and opens toward the top of the coordinate grid.

Hope this helps!

6 0
2 years ago
What is the surface area of the rectangular prism?
Nadusha1986 [10]
348 in. 2

2·(8·9+6·9+6·8)=348
7 0
3 years ago
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