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3 years ago

Solve the following problem. 4/10 ÷ 1/3 =

2 answers:

4 0

0.4/0.3=1.3
1.3 is the answer
You have to divide 4/10 and 1/3 and what ever two answers you get from there is the two that you divide

wolverine [178]3 years ago

4 0

Answer:

Decimal Form: 1.2

Mixed Numbered Form:1 1/5

Exact Form: 6/5

Step-by-step explanation:

//Give thanks(and or Brainliest) if helpful (≧▽≦)//

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Describe how to find all the points on a baseball field that are equidistant from second base and third base.

Zielflug [23.3K]

From the given diagram, the following statements are true:

AB = BC

3y = 5y - 22

3y - 5y = -22

-2y = -22

y = 11

Similarly, m<DBE = 50 degrees

m<BED = 90 - m<DBE

m<BED = 90 - 50

m<BED = 40 degrees

Since BE = BC = 3y

BE = BC = 3(11) = 33

Also, 7x - 2 = 40

7x = 40 + 2

7x = 42

x = 6

Get the measure of m<BEA

m<BEA = 7x - 2

m<BEA = 7(6) - 2

m<BEA = 40 degrees

Learn more on angles here: brainly.com/question/16281260

8 0

3 years ago

What irrational number is in between 9.6 and 9.7, please help me Mr. Aizawa is gonna kill me if i don't get my "easy" homework f

Eduardwww [97]

Answer:

goku solos mha universe

Step-by-step explanation:

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3 0

3 years ago

Read 2 more answers

I had $20.00. My Mom gave me $10.00. My Dad gave me $30.00. My Aunt and Uncle gave me $100.00. I had another $1.00 How much did

Ainat [17]

Answer:

161 dollars

Step-by-step explanation:

What we know:

1. beginning value = 20 dollars

2. +10 dollars from mom

3. +30 dollars from dad

4. +100 dollars from aunt and uncle

5. +1 dollar

Add the values

20+10+30+100+1

= 161 dollars

I hope this helps!

5 0

3 years ago

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A silo contains 60,000 pounds of grain how many tons are in 60,000 pounds?

Mnenie [13.5K]

Answer:

30 tons

Step-by-step explanation:

4 0

3 years ago

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Integrate e^x(sin(x) cos(x))

Karo-lina-s [1.5K]

$I=\int e^x(\sin(x)\cos(x))dx=\int e^x(\frac{1}{2}\sin(2x))dx=\frac{1}{2}\int e^x\sin(2x)dx$

$\text{If }u=\sin(2x)\to du=2\cos(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
\text{Using }\int u\,dv=uv-\int v\,du:\\\\
I=\frac{1}{2}(e^x\sin(2x)-\int e^x(2\cos(2x))dx)\\\\
2I=e^x\sin(2x)-2\underbrace{\int e^x\cos(2x)dx}_{I_2}$

Looking for $I_2$ :

$\text{If}~u=\cos(2x)\to du=-2\sin(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
I_2=e^x\cos(2x)-\int e^x(-2\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(2\sin(x)\cos(x))dx\\\\ I_2=e^x\cos(2x)+4\int e^x(\sin(x)\cos(x))dx=e^x\cos(2x)+4I$

Replacing:

$2I=e^x\sin(2x)-2I_2\iff\\\\2I=e^x\sin(2x)-2(e^x\cos(2x)+4I)\iff\\\\
2I=e^x\sin(2x)-2e^x\cos(2x)-8I\iff\\\\
10I=e^x\sin(2x)-2e^x\cos(2x)\iff\\\\
I=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))\\\\
\boxed{\int e^x(\sin(x)\cos(x))dx=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))+C}$

6 0

3 years ago