All categories

3 years ago

Please answer This Just Try Don't skip

Mathematics

2 answers:

Sav [38]3 years ago

7 0

(i)
Area of rectangle = length * breadth
So,
x^2 - 12x + 35 = (x - 5) * breadth

Factorize area and divide by length to simplify.
=> {(x-5)(x-7)} / (x-5) = breadth
=> x-7 = breadth

Therefore, breadth = 7

(ii)
Length = 10 - 5 = 5m
Breadth = 10 - 7 = 3m
Area = 10^2 - 12(10) + 35 = 15sq.m

attashe74 [19]3 years ago

4 0

Answer:

5 m , 3 m , 15 m²

Step-by-step explanation:

Given area (A) = x² - 12x + 35 and A = length × breadth , then

x² - 12x + 35 = (x - 5)(x - 7) ← in factored form

We know length = x - 5 , then breadth = x - 7

When x = 10

length = x - 5 = 10 - 5 = 5 m and breadth = x - 7 = 10 - 7 = 3 m

A = 10² - 12(10) + 35 = 100 - 120 + 35 = 15 m²

A = length × breadth = 5 × 3 = 15 m²

You might be interested in

In a hostel, 80 students have food enough for 45 days. How many students should leave the hostel so that the food is enough for

Aleonysh [2.5K]

Say that taking a quarter of student out of the group will add a quarter present of days for food so by take 20 students out you’ll get 60 days (that’s what I got hope this helps)

4 0

2 years ago

What is the primary goal and secondary goal of the Fried Liver Opening in chess? <br />

polet [3.4K]

Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.

Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.

3 0

3 years ago

HELP HELP PLEASE I NEED HELP

dimaraw [331]

Answer:

<h2>FALSE</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

PEMDAS

<h3>tips and formulas:</h3>

order of PEMDAS

parentheses
exponent
multiplication or
division
addition
subtraction

left to right

<h3>let's solve:</h3><h2><u>L.</u><u>H.S</u><u>=</u></h2>

<u> $\sf simplify \: divition: \\ \tt 14 + 33 + 0.4$ </u>
<u> $\sf simplify \: additio n : \\ \tt 47.4$ </u>

therefore

<h3>the equality is false</h3>

8 0

3 years ago

Find the equation of the circle with center at

Vinvika [58]

Radius (R) is equal to the distance between the points (-2,1) and <span>(3,1)
R</span>² = (-2 - 3)² + (1 - 1)² = (-5)² + 0 = 25
R = 5

<span>Equation of the circle:
</span>(х-(-2))² + (у-1)² = 5²
(х+2)² + (у-1)² = 25

4 0

3 years ago

A freight company has shipping orders for two products. The first product has a unit volume of 10 cu ft and weighs 50 lb. The se

nydimaria [60]

Answer:

Number of units of first product = 112

Number of units of second product = 400

Step-by-step explanation:

Given that there are two products which are to be shipped.

<em>First product details:</em>

Unit volume = 10 cu ft

Weight of one unit = 50 lb

<em>Second product details:</em>

Unit volume = 3 cu ft

Weight of one unit = 40 lb

Total volume that can be carried by a truck = 2320 cu ft

Total weight that can be carried by a truck = 21600 cu ft

To find:

The number of units of each product that can be transported in one shipment in the truck?

Solution:

Let number of units of first product = $x$

Let number of units of second product = $y$

We can write down two linear equations in two variables here and solving them will give us the answer we are required to find.

As per question statement, the equations can be written as:

$10x+3y = 2320 ...... (1)\\50x+40y = 21600\\\Rightarrow 5x+4y = 2160...... (2)$

Multiplying equation (2) with 2 and subtracting equation (1) from it:

$8y - 3y = 4320-2320\\\Rightarrow 5y = 2000\\\Rightarrow \bold{ y = 400}$

By equation (1):

$10x+1200 = 2320\\\Rightarrow 10x = 1120\\\Rightarrow \bold{x = 112}$

Answer is:

Number of units of first product = 112

Number of units of second product = 400

6 0

2 years ago

Please answer This Just Try Don't skip​

Please answer This Just Try Don't skip