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2 years ago

Please help me with #8-9. PLEASE!!!

Mathematics

1 answer:

Firdavs [7]2 years ago

6 0

8a . the constant of proportionality is 2. 8b . the constant of proportionality is 3. 9. Nathan should order 1 cup of each food on the chart. <span />

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If cos x=8/17, and 270° < x < 360°<br> what is cos(2x)?

svp [43]

Answer: $\bold{-\dfrac{161}{289}}$

<u>Step-by-step explanation:</u>

Given: cos x = $\dfrac{8}{17}$ , x is in Quadrant 4

Use Pythagorean Theorem to find sin x:

8² + y² = 17²

y² = 17² - 8²

y² = 289 - 64

y² = 225

y = 15

→ sin x = $-\dfrac{15}{17}$

Use the double angle formula to find cos (2x):

$cos (2x) = cos^2 x - sin^2 x\\\\.\qquad=\bigg(\dfrac{8}{17}\bigg)^2-\bigg(-\dfrac{15}{17}\bigg)^2\\\\\\.\qquad=\dfrac{64}{289}-\dfrac{225}{289}\\\\\\.\qquad=-\dfrac{161}{289}$

8 0

3 years ago

Read 2 more answers

Evaluate 8-m/n +m when m=8 and n=2

RUDIKE [14]

Substitute the answer: therefore, 8-8/2+8= 0/10 in fraction form, but as you feather simplify 0 divide by 10 you'll get the answer as 0.

3 0

3 years ago

Which expression represents the product of 3 and y? 3 + y 3 − y 3 over y 3y

Eva8 [605]

Answer:

3y is the expression that represents the product of 3 and y

5 0

3 years ago

How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ

sattari [20]

<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)

(1 -sin^2(θ))cot^2(θ) = . . . . . replace cos^2 with 1-sin^2

cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin

cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired

8 0

3 years ago

If a square has an area of 225 square feet what is the length of each side

sdas [7]

The area of the square: $A=a^2$

where "a" is a length of side.

Therefore:
$A=225\ ft^2\ and\ A=a^2\Rightarrow a^2=225\Rightarrow a=\sqrt{225}\Rightarrow \boxed{a=15\ (ft)}$

3 0

3 years ago