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rjkz [21]
3 years ago
15

Give an example of a real-world situation involving two unknown quantities. Then write an algebraic expression to represent the

situation.
Mathematics
2 answers:
Stels [109]3 years ago
7 0

Answer:

t=\frac{15}{s} represents the situation described below.

Step-by-step explanation:

A real-world situation could be

<em>Mary is runs everyday, she runs 15 kilometers per day, if she move at a constant speed, what would be the ratio that represents the time she needs everyday to make 15 kilometers.</em>

<em />

In this example, we have three quantities, distance traveled, speed and time. But, we already now the distance traveled, and we don't know the speed and time Mary uses to make 15 kilometer. We also know that the movement is constant, so it's defined by

s=\frac{d}{t}

Where s is speed, d is distance and t is time. So, if d=15, the ratio that represents time would be

s=\frac{d}{t}\\ t=\frac{d}{s}\\ t=\frac{15}{s}

Therefore, the algebraic expression that represents the hypothetical situation is

t=\frac{15}{s}

Where t is time and s is speed.

RUDIKE [14]3 years ago
3 0
A real world expression would be Toby had makes 3 dollars per hour he wants to buy a ps4 for 40 dollars. he already has 10 dollars. how many hours does he have to work to afford his ps4. 3x+10=40
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Y = x + 2<br> y = 2x - 5<br> what is x and y
lana66690 [7]

Answer:

x= 7 y= 9 (7,9)

Step-by-step explanation:

solve by using system if equations. multiply top answer by 2, giving u 2y=2x+4 and y=2x-5 subtract the equations. y=9 (the x cancels out) then put 9 in for y. 9=x+2. subtract 2. giving u 7. and now x =7

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2 years ago
(1 point) Two six-sided dice are rolled (one red one and one green one). Some possibilities are (Red
anygoal [31]

Complete question:

Two six-sided dice are rolled (one red one and one green one). Some possibilities are (Red= 1, Green=5) or (Red=2, Green=2) etc.

a)How many total possibilities are there?

For the rest of the questions, we will assume that the dice are fair and that all the possibilities in (a) are equally likely.

b)What is the probability that the sum on the two dice comes out to be 11?

c)What is the probability that the sum on the two dice comes out to be 7?

d)What is the probability that the numbers on the two dice are equal?

Answer:

Kindly check explanation

Step-by-step explanation:

Total probabilities :

Total possible outcomes on each dice = 6

Total probabilities = 6² = 36

b)What is the probability that the sum on the two dice comes out to be 11?

Total required outcome = 2

Total possible outcomes = 36

Probability = required outcome / Total possible outcomes

P(sum on both dice = 11) = 2 / 36 = 1/18

c)What is the probability that the sum on the two dice comes out to be 7?

Required outcome = 6

Possible outcomes = 36

P(obtaining a sum of 7) = 6/36 = 1/6

d)What is the probability that the numbers on the two dice are equal

= required outcome / possible outcomes

Required outcome = 1,1 ; 2,2; 3,3; 4,4 ; 5,5 ; 6,6

= 6/36 = 1/6

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