Answer:
Antibodies
Explanation:
Bordetella pertussis is an obligate human pathogen and is the etiological agent of whooping cough. It is known to be an opportunistic organism.
The pathogenic mechanism of Bordetella pertussis is also known as virulence factor. These virulence factors are known to include adhesins such as filamentous haemagglutinin, fimbriae and pertactin, which allow B. pertussis to bind to ciliated epithelial cells in the upper respiratory tract.
It is known to be the agent of whooping cough, a highly contagious respiratory disease, dramatic for infants and also for elderly and pregnant women.
In this case, the antibodies will be the response that is uniquely directed against the organism. It is said earlier that this organism is an opportunistic one, this means that it causes infection when the immunity is down. So, when the immunity is empowered , it will definitely fight against the organism
The best answer is B.
The endosymbiotic theory states that mitochondria and chloroplasts have striking similarities to bacterial cells:
1. they have their own DNA, which is separate from the DNA found in the nucleus of the cell.
2. Both organelles use their DNA for to produce many proteins and enzymes required for function.
3. They are both surrounded by a double membrane.
4. They reproduce just the way bacteria do, replicating their own DNA and directing their own division.
Answer:
a) 
b) 
c) 
d) 
e) 
Explanation:
When two heterozygous plants with genotype Bb are crossed, following offspring are produced
Bb * Bb
BB, Bb, Bb, bb
so the probability of blue offspring is
and the probability of white offspring is 
a) Probability of all 4 peas as blue

b) Probability of 3 blue and 1 white

c) Probability of 2 blue and 2 white

d) Probability of 1 blue and 3 white

e) Probability of all white
