Area is defined as the space covered by any object in the two dimensional plane. Here it is given that the area of the rug should be 40 square feet and the length of the rug is 3 less then its width.

So to find out the length and the width we will form an equation.

Let the width is = x feet

So the length will be = x-3 feet

Now the area will be

$x(x-3)=40$

$x^2-3x-40=0$

By solving the quadratic equation

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-3)\pm\sqrt{9+(4\times1\times40}}{2}$

$x=\dfrac{3\pm13}{2}$

$x=8 \ and \ \ x=-5.5$

Here the value of x will be positive because length cant be negative.

So the width of the rug will be x=8 feet

Length of the rug will be x-3= 8-3=5 feet

Hence the length and the width of the rug having an area of 40 square feet will be 5 feet and 8 feet respectively.

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7 0

3 years ago

Algebra 2 math question

mafiozo [28]

Answer:

500 = 38t

Step-by-step explanation:

let x = minutes

f(x) = 500 + 38x

500 = 38t

graph

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6 0

3 years ago

ASAP PLS HELP ILL GIVE U A COOKIE

Dvinal [7]

Answer:

x = 11

Step-by-step explanation:

7 0

3 years ago

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