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yawa3891 [41]
3 years ago
14

A bag contains 5 red balls. What is the probability that you draw a red ball out of the bag?

Mathematics
2 answers:
Fiesta28 [93]3 years ago
8 0
There is a 100% chance because the bag only contains red balls.

If other wise put the 5 over the total number of balls. That would be your answer unless it can be put into simplest form.
alex41 [277]3 years ago
4 0
It is 100% because there is only 5 red balls.
The math:

(5/5) x 100%
1 x 100%
= 100%

hope this helps :)



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3 years ago
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\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Similarities.

Since here, first figure is a Triangle, hence similarity of a triangle is given by ratio of it sides and make them equate,

hence for,

1.) 16/12 = x/9 ===> 4/3 = x/9 ===> x = 9*4/3 ==> x = 36/3

hence the value of x is 12 , ===> x = 12 .

2.) here,in the case of a Reactangle the relation is such that, length = 2* breadth,

hence we apply the relation,

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3 years ago
Does anybody have their geometry notebook for E2020? I need it to get credit for the course but I lost mine.
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Step-by-step explanation:

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3 years ago
Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,
Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁,  of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}

Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times  (720-576)\times  (720 - 672)}

Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times  144 \times  48} = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}

The semi-perimeter, s₂,  of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times  (690 -228)\times  (690 - 480)}

Area\, of \, \Delta ACD = \sqrt{690 \times 18\times  462\times  210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0
3 years ago
tess has 100 dimes and quarters , if the total of the coins is $21.40 how many of each of the coins does she have ?? Using subst
Zanzabum

Answer: 24 and 76

Step-by-step explanation:

{

d

+

q

=

100

10

d

+

25

q

=

2140

From the first equation, we have  

d

=

100

−

q

Substituting that into the second equation, we have

10

(

100

−

q

)

+

25

q

=

2140

⇒

1000

−

10

q

+

25

q

=

2140

⇒

15

q

=

1140

⇒

q

=

1140

15

=

76

Knowing that  

q

=

76

we can substitute that value into the first equation to obtain

d

+

76

=

100

∴

d

=

24

Thus, Sue has  

24

dimes and  

76

quarters.

4 0
3 years ago
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