The required simplified value of b + g is 21.
Given that,
At a classroom costume party, the average age of the b-boys is g, and the average age of the g girls is b.
The average age of everyone at the party (all these boys and girls, plus their 42- year-old teacher) is b+g,
<h3>What is average?</h3>
The average of the values is the ratio of the total sum of values to the number of values.
Here,
The average age of the b-boys is g.
The average age of the g-girls is b.
The average age of everyone at the party (all these boys and girls, plus their 42-year-old teacher) is b+g,
Now,
average of n = 3 (b , g , b+g)
Average = g + b + 42 / 3
b + g = (b + g + 42 ) / 3
3b + 3g = b + g + 42
3b - b + 3g - g = 42
2b + 2g = 42
2 (b + g) = 42
b + g = 21
Thus, the required simplified value of b + g is 21.
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-0.666666 (it’s recurring)
The hypothesis test shows that we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%
<h3>What is the claim that the return rate is less than 20% by using a statistical hypothesis method?</h3>
The claim that the return rate is less than 20% is p < 0.2. From the given information, we can compute our null hypothesis and alternative hypothesis as:


Given that:
Sample size (n) = 6965
Sample proportion 
The test statistics for this data can be computed as:



z = -2.73
From the hypothesis testing, since the p < alternative hypothesis, then our test is a left-tailed test(one-tailed.
Hence, the p-value for the test statistics can be computed as:
P-value = P(Z ≤ z)
P-value = P(Z ≤ - 2.73)
By using the Excel function =NORMDIST (-2.73)
P-value = 0.00317
P-value ≅ 0.003
Therefore, we can conclude that since P-value is less than the significance level at ∝ = 0.01, we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%
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Step-by-step explanation: we can not drag anything so please try to get that to work thank you!