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yulyashka [42]
3 years ago
11

Suppose J=[−2365]. What is the value of |J|? Enter your answer in the box.

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

The determinant of J can be found using the formula ad - bc

where   \left[\begin{array}{cc}a&b\\c&d\end{array}\right]

So we have -2 * 5 - 6 * 3 = -10 - 18 = -28

Step-by-step explanation:

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Simplify each expression: <br> a)4a-3+5a<br> b)t-3t+2t+4<br> c) 3(g+5)+2g<br> d)2t+4)3+6(-5t)-(-8)
Vlad1618 [11]

Answer:

there you go it's all the paper

8 0
3 years ago
one sixth of the students in a school marching band are in the percussion section, the percussion section has 6 students, how ma
Igoryamba

Answer:

36 students

Step-by-step explanation:

because if 1/6 is 6 students then you have to multiply the 6 by 6

4 0
3 years ago
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A circle has a radius of 5. Express in term of pi the circumference of the circle
Natalka [10]
Circumference of a circle = 2pir
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3 0
3 years ago
Please help please please
hammer [34]

Answer:

A. The lines stay parallel

Step-by-step explanation:

Rigid transformations do not change angle or line relationships. When the parallel lines are rotated they stay parallel. Reflecting them will keep them parallel. If this were not true, then figured with parallel lines like rectangles and squares would change shape when reflected.

4 0
3 years ago
Match the information on the left with the appropriate equation on the right.
solmaris [256]

Answer:

Step-by-step explanation:

1). Equation of a line which has slope 'm' and y-intercept as 'b' is,

y = mx + b

If slope 'm' = 1 and y-intercept 'b' = -3

Equation of the line will be,

y = x - 3

x - y = 3

2). Equation of a line having slope 'm' and passing through a point (x', y') is,

y - y' = m(x - x')

If the slope 'm' = 1 and point is (-1, 2),

The the equation of the line will be,

y - 2 = 1(x + 1)

y = x + 1 + 2

y = x + 3

x - y = -3

3). Equation of a line passing through two points (x_1, y_1) and (x_2,y_2) will be,

y-y_1=\frac{(y_2-y_1)}{(x_2-x_1)}(x-x_1)

If this line passes through (-2, 3) and (-3, 4),

y-3=\frac{(4-3)}{(-3+2)}(x+2)

y - 3 = -1(x + 2)

y = -x - 2 + 3

y = -x + 1

x + y = 1

4 0
3 years ago
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