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Law Incorporation [45]
3 years ago
6

Hey, I would appreciate it if you can help me with these problems, been stuck on it for a few days

Mathematics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

Explained below.

Step-by-step explanation:

The formula for average rate of change is:

\frac{f(b) - f(a)}{b - a}

1. \frac{f(b) - f(a)}{b - a} = \frac{f(2) - f(1)}{2 - 1} =  \frac{100 - 40}{2 - 1} =  \frac{70}{1} = 70

2. \frac{f(b) - f(a)}{b - a} = \frac{f(4) - f(2)}{4 - 2} = \frac{180 -110}{4 - 2} = \frac{70}{2} = 35

3. \frac{f(b) - f(a)}{b - a} = \frac{f(8) - f(6)}{8 - 6} = \frac{350 -230}{8 - 6} = \frac{120}{2} = 60

4. \frac{f(b) - f(a)}{b - a} = \frac{f(10) - f(8)}{10 - 8} = \frac{390 -350}{10 - 8} = \frac{40}{2} = 20

5. Their average speed was the greatest during the first to second hour.

6. Their average speed was the least during the eight to tenth hours.

7. \frac{f(b) - f(a)}{b - a} = \frac{f(10) - f(1)}{10 - 1} = \frac{390 -40}{10 - 1} = \frac{350}{9} = 38.89 or 38.9

Hope that helps!

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14.       1.5, 10    <- Answer
15.       5,1          <- Answer

Proof 14 

Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5               
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Proof 15. 

Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer:  {x = 5                           y = 1
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