<h2><u>Solu</u><u>tion</u><u>:</u></h2>
360° ÷ 10 ÷ 2 = 18°
So the length of the decagon side is:
10 × tan18° × 2 = 20 × tan18°
The area is: ½ × 20 × tan18° × 10 × 10 = 1000 × tan18°
≈ 324.9
.: <u>3</u><u>2</u><u>4</u><u>.</u><u>9</u> is the final answer.
<em>I</em><em> </em><em>h</em><em>ope</em><em> </em><em>this</em><em> helps</em><em>. </em>
Answer:
$12
Step-by-step explanation:
60.00 meal
x 20percent tip
you convert the 20 percent to .20
so 60
x .20
------------
12.00
The probability of being 25-35 years and having a haemoglobin level above 11 is 34%.
The probability of having a haemoglobin level above 11 is 36%.
Being 25-35 years and having a hemoglobin level above 11 are not dependent on each other.
<h3>What are the probabilities?
</h3>
Probability determines the odds that a random event would occur. The odds of the event happening lie between 0 and 1.
The probability of being 25-35 years and having a haemoglobin level above 11 = number of people between 25 - 35 that have a level above 11 / total number of people between 25 - 35
44 / 128 = 34%
The probability of having a haemoglobin level above 11 = number of people with a level above 11 / total number of respondents
153 / 429 = 36%
To learn more about probability, please check: brainly.com/question/13234031
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Is it 360 or 53 I think it’s 360
Answer:
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.2622
The margin of error is:
M = T*s = 2.2622*0.3 = 0.68
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF
The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF
The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF
