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musickatia [10]
3 years ago
10

What is the value of the expression (e+c-d)x dn when e=-6, n=2, c=6, and d=-1

Mathematics
1 answer:
saul85 [17]3 years ago
8 0

The value of the expression (e+c-d)x dn  is -2

The given expression is:

(e+c-d)x dn

Substitute e=-6, n=2, c=6, and d=-1 into (e + c - d)  x  dn

(e+c-d)x dn  =  [-6  + 6 -(-1)]  x  (-1)(2)

(e+c-d)x dn  =  (0  +  1)   x  (-2)

(e+c-d)x dn  =  1   x  (-2)

(e+c-d)x dn  =   -2

Learn more here: brainly.com/question/13961297

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Here are both the answers at once to make it easier for you: 
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