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Mariana [72]
3 years ago
10

You run out of gas and measure the amount of gas it takes to fill the tank. Is this data a type discrete or continuous

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0

I think it is continuous

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1st question I want to solve
mr_godi [17]

Answer:

34.64

Step-by-step explanation:

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7 0
2 years ago
Cot^2x csc^2x + 2 csc^2x –cot^2 = 2
kow [346]

Answer:

x = π/2 + πk

Step-by-step explanation:

cot² x csc² x + 2 csc² x − cot² x = 2

Multiply both sides by sin² x:

cot² x + 2 − cos² x = 2 sin² x

Add cos² x to both sides:

cot² x + 2 = 2 sin² x + cos² x

Pythagorean identity:

cot² x + 2 = sin² x + 1

Subtract 1 from both sides:

cot² x + 1 = sin² x

Pythagorean identity:

csc² x = sin² x

Multiply both sides by sin² x:

1 = sin⁴ x

Take the fourth root:

sin x = ±1

Solve for x:

x = π/2 + 2πk, 3π/2 + 2πk

Which simplifies to:

x = π/2 + πk

4 0
3 years ago
What is the rule for the reflection?
zloy xaker [14]
The answer is C because if you put
x =  - 2 \\ y = 1 \\
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They're just flipped equations
3 0
3 years ago
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The student council sells cookies every 9 days and ice cream every 12 days. If both are being sold today, how many days will it
blondinia [14]
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6 0
3 years ago
Read 2 more answers
Please help it’s urgent
katrin2010 [14]

\bold{\text{Answer:}\quad \dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

<u>Step-by-step explanation:</u>

.\quad \dfrac{-5x}{8x+7}-\dfrac{6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}+\dfrac{-6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}\bigg(\dfrac{3x+1}{3x+1}\bigg)+\dfrac{-6x^3}{3x+1}\bigg(\dfrac{8x+7}{8x+7}\bigg)\\\\\\=\dfrac{-15x^2-5x}{(8x+7)(3x+1)}+\dfrac{-48x^4-42x^3}{(8x+7)(3x+1)}\\\\\\=\large\boxed{\dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

5 0
3 years ago
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