$\bf \begin{cases} f(x)=x+2\\[1em] g(x)=\cfrac{9}{x^2}\\[-0.5em] \hrulefill\\ (f\circ g)(x)\implies f(~~g(x)~~) \end{cases}\qquad \qquad f(~~g(x)~~)=[g(x)]+2 \\\\\\ f(~~g(x)~~)=\left[ \cfrac{9}{x^2} \right]+2\implies f(~~g(x)~~)=\cfrac{9}{x^2}+2$

6 0

3 years ago

To qualify for the championship a runner must complete the race in less than 55 minutes ....... Use "t" to represent the time in

Svet_ta [14]

The inequality is t < 55

Solution:

Given that, To qualify for the championship a runner must complete the race in less than 55 minutes

Let "t" represent the time in minutes of a runner who qualifies for the championship

Here it is given that the value of t is less than 55 minutes

Therefore, "t" must be less than 55, so that the runner qualifies the championship

This is represented by inequality:

$t$

The above inequality means, that time taken to complete the race must be less than 55 for a runner to qualify

Hence the required inequality is t < 55

3 0

3 years ago

Mr. Blake took 10 minutes to drive 5 miles,

Sav [38]

Answer:

The correct answer is - 3, 4, and 5.

Step-by-step explanation:

Given:

distance = 5 miles

time to cover 5 miles = 10 minutes

If his claim is true then,

additional Distance = 15 miles

total distance will be = 15+5 = 20 miles

additional time = 30 minutes

total time = 10+30 = 40 minutes

Solution:

The speed of the vehicle can be calculated by the formula:

V = d/t

where V is speed or velocity

d = distance

t = time

Putting the final or total values in formula =

V = 20/40

= 1/2 (5th statement is true)

In an hour where 60 minutes are there, 1/2 = 30 miles per hour.

Thus, 3rd and 4th statement are true.

8 0

3 years ago