Answer:
2a(7b+5)
Step-by-step explanation:
yeah-ya....... right?
Answer:
P_max = 9.032 KN
Step-by-step explanation:
Given:
- Bar width and each side of bracket w = 70 mm
- Bar thickness and each side of bracket t = 20 mm
- Pin diameter d = 10 mm
- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa
- Average allowable shear stress of pin S = 115 MPa
Find:
The maximum force P that the structure can support.
Solution:
- Bearing Stress in bar:
T = P / A
P = T*A
P = (120) * (0.07*0.02)
P = 168 KN
- Shear stress in pin:
S = P / A
P = S*A
P = (115)*pi*(0.01)^2 / 4
P = 9.032 KN
- Bearing Stress in each bracket:
T = P / 2*A
P = T*A*2
P = 2*(120) * (0.07*0.02)
P = 336 KN
- The maximum force P that this structure can support:
P_max = min (168 , 9.032 , 336)
P_max = 9.032 KN
Answer:
Step-by-step explanation:
Answer:
<2 = 75°
<3 = 75°
Step-by-step explanation:
<2 = <6
2x+15 = 45+x
or, 2x-x = 45-15
or, x = 30
so, <2 = 30×2+15 = 75
<6 = 45+30 = 75
Answered by GAUTHMATH
Answer:
I am sorry I really don't know I will try to help if I get it sorry :((
Step-by-step explanation:
