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Stella [2.4K]
2 years ago
5

Riley wants to solve 54 Divided 6=_

Mathematics
2 answers:
blondinia [14]2 years ago
8 0

Answer:

YES      (9 x 6 = 54)

NO       (9 + 6 = 15)

NO       (60 – 6= 54 )

Step-by-step explanation:

54 divided by 6 means "which number, multiplied by 6, gives 54?". 9 x 6 = 54 answers this question, so it's the correct equation to use.

Hope this helps!

dedylja [7]2 years ago
7 0
First equation- yes
second equation- no
third equation- no
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I need help with this homework question
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64/16=4
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Solve the inequality.<br> 1<br> x+5 &lt; 6<br> 2<br><br> Help me please
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Answer:

If we are solving x + 5< 6 the inequality is x< 1

Step-by-step explanation:

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Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

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For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

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If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

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                                     x+y=2\\2x-y=1

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From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

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                                            x=2-1\\x=1

So, there is an unique solution to this equations:

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Answer:

Not sure if this is right but it might be something like

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Step-by-step explanation:

The numbers we know are 350,000 4% and 1671 per month

350,000 is the full mortgage

4% is the APR or annual percentage rate like interest

and we know the monthly for the mortgage is 1671 per month

4 0
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