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Otrada [13]
2 years ago
10

What is. 3/4x - 2/3x - 4 = 1/6x - 7 I give Brainliest!

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
4 0

Answer:

x = 36

Step-by-step explanation:

(3/4)*x-((2/3)*x)-4 = (1/6)*x-7 // - (1/6)*x-7

(3/4)*x-((2/3)*x)-((1/6)*x)-4+7 = 0

(3/4)*x+(-2/3)*x+(-1/6)*x-4+7 = 0

3-1/12*x = 0 // - 3

-1/12*x = -3 // : -1/12

x = -3/(-1/12)

x = 36

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Write an expression for the perimeter of the triangle shown below:
AveGali [126]

Answer:

The answer is 0.1x-16

Step-by-step explanation:

-3.4x+3x+.5x=0.1x and -25+9 is -16  which is 0.1x-16

6 0
3 years ago
Two siblings' ages have a sum of 64 years. The older sibling was born 6 years before their young sibling.
Elina [12.6K]

Hi!

So we have to make a system of equations here.

Let sibling 1 be O and sibling 2 be Y (for older and younger)

So:

O + Y = 64

O = 64 - Y

(Either one works)

The older sibling is 6 years older.

O = Y + 6

Make everything in terms of Y.

64 - Y = Y + 6

Same to both:

58 = 2y

2y = 58

Divide by 2 on both sides:

y = 29

Since the older sibling is 6 years older:

29 + 6 = 35

Y = 29

O = 35

Let me know if you have any questions.

4 0
2 years ago
Find the sequence of -1, 1, __, 5, __
marin [14]
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7 0
2 years ago
Question 4 (Fill-In-The-Blank Worth 6 points)
Marrrta [24]
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5 0
3 years ago
NAND"" and ""NOR"" circuits are commonly used as a basis for flash memory chips. A NAND B is defined to be the negation of ""A a
Anit [1.1K]

Answer:

(i) A truth table shows how the truth or falsity of a compound statement depends on the truth or falsity of the simple statements from which it's constructed.

Since A ∧ B (the symbol ∧ means A and B) is true only when both A and B are true, its negation A NAND B is true as long as one of A or B is false.

Since A ∨ B (the symbol ∨ means A or B) is true when one of A or B is true, its negation A NOR B is only true when both A and B are false.

Below are the truth tables for NAND and NOR connectives.

(ii) To show that (A NAND B)∨(A NOR B) is equivalent to (A NAND B) we build the truth table.

Since the last column (A NAND B)∨(A NOR B) is equal to (A NAND B) it follows that the statements are equivalent.

(iii) To show that (A NAND B)∧(A NOR B) is equivalent to (A NOR B) we build the truth table.

Since the last column (A NAND B)∧(A NOR B) is equal to (A NOR B) it follows that the statements are equivalent.

6 0
3 years ago
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