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Nastasia [14]
3 years ago
13

Need help asap I will marks as brainliest ​

Computers and Technology
1 answer:
ra1l [238]3 years ago
3 0

Answer:

<em>1</em><em>.</em><em> </em><em>is</em><em> </em><em>true</em>

<em>2</em><em>.</em><em> </em><em>is</em><em> </em><em>true</em>

<em>3</em><em>.</em><em>is</em><em> </em><em>true</em>

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Two boxes overlap if their interiors have at least one point in common. Give an O(n log n)-time algorithm that decides if there
GaryK [48]

Answer:

// Program is written in C++ programming language

// The program checks if two boxes overlap and prints both boxes

// Comments are used for explanatory purpose

// Program starts here

#include<bits/stdc++.h>

#include <graphics.h>

#include <conio.h>

// Define x and y axis

struct axis { int x, y; };

bool checkRect(Axis l1, Axis r1, Axis l2, Axis r2)

{ // l1, l2, r1 and r2 represent the left and right coordinates of both rectangles

// Check one rectangle is on left side of other

if (l1.x > r2.x || l2.x > r1.x) {

return false; }

// Check if one rectangle is above other

if (l1.y < r2.y || l2.y < r1.y) {

return false; }

return true;

}

// Main Method begins here

int main()

{

// Declare integer variables to enter rectangle coordinates

// For rectangle 1

int left1, left2, right1, right2;

cout<<"Enter First rectangle coordinates: "<<"\n";

cout<<"Top Left: "<<"\n";

cin>>left1;

cout<<"Bottom Left: "<<"\n";

cin>>left2;

cout<<"Top Right: "<<"\n";

cin>>right1;

cout<<"Bottom Right: "<<"\n";

cin>>right2;

// For rectangle 2

int left3, left4, right3, right4;

cout<<"Enter Second rectangle coordinates: "<<"\n";

cout<<"Top Left: "<<"\n";

cin>>left3;

cout<<"Bottom Left: "<<"\n";

cin>>left4;

cout<<"Top Right: "<<"\n";

cin>>right3;

cout<<"Bottom Right: "<<"\n";

cin>>right4;

Axis l1 = {left1, left2}, r1 = {right1, right2};

Axis l2 = {left3, left4}, r2 = {right3, right4};

if (checkRect(l1, r1, l2, r2)) {

cout<<"The Rectangles Overlap"; }

else {

cout<<"Rectangles Don't Overlap";}

// Print Rectangle 1

rectangle (left1, right1, left2, right2);

// Print Rectangle 2

rectangle (left3, right3, left4, right4);

return 0;

}

5 0
3 years ago
In the Happy Valley School System, children are classified by age as follows: less than 2, ineligible 2, toddler 3-5, early chil
sasho [114]

// C++ switch

// It can also be used for JAVA, C#

switch(age){

// here age will be sent by the function in which it is used

// case to check the age<2

case(age<2 && age>0):

// printing the line

cout<<"ineligible";

// case to check the age ==2

case(age==2):

// printing the line

cout<<"toddler";

// case to check 3-5

case(age>=3 && age<=5):

cout<<"early childhood";

// case to check 6-7

case(age==6 || age==7):

cout<<"young reader";

//case to check 8-10

case(age>=8 && age<=10):

cout<<"elementary";

// case to check 13

case(age==13):

cout<<"impossible";

//case tocheck 14-16

case(age>=14 && age<=16):

cout<<"high school";

// case to check 17 or 18

case(age==17 || age==18):

cout<<"scholar";

//case to check >18

case(age>18);

cout<<"ineligible";

// default case

default:

cout<<"Invalid age";

}

Read more on Brainly.com - brainly.com/question/12981906#readmore

5 0
3 years ago
What are some random fun facts about Technology?
Lana71 [14]

Answer:

i do not know

Explanation:

but it helps to communication

5 0
3 years ago
Why is it worth remembering “All people seem to need data processing”?
Rzqust [24]
The answer is .........C
3 0
4 years ago
Read 2 more answers
Please help me idk I suck at this stuff ​
kap26 [50]
I would say the best clear answer is D, because A is a little bit unclear but I would say the best answer is D.

Why?

Mesh Topology is expensive considering more links as compared to Ring topology.


4 0
3 years ago
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