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nadya68 [22]
2 years ago
12

como la ciencia y tecnologia ayudan a reducir la contaminacion del aire que respiramos? Muestra algunos ejemplos

Computers and Technology
1 answer:
Llana [10]2 years ago
4 0
  • Mediante la tecnología se han implementado el uso de medios de transporte como los "coches verdes" o eléctricos que contribuyen a disminuir la producción de  gases contaminantes atmosféricos.

A través de la ciencia y la biotecnología se ha avanzado en el campo de la purificación del aire algunas de las herramientas que actualmente se están utilizando son:

  • La biofiltraccion del aire que se realiza a través de macroporos de material filtrante por donde se filtran los compuestos orgánicos e inorgánicos atmosféricos. También es posible realizar la biodepuracion del aire con plantas purificantes y ornamentales.

  • El uso de las paredes arbóreas cubiertas de musgo ha permitido que en algunas ciudades como París y Berlín mejore la calidad del aire,ya que el musgo se caracteriza  por su gran capacidad para  filtrar contaminantes del aire como las partículas y los óxidos de nitrógeno ya que  los convierte en purificadores naturales ideales para el medio ambiente.

Lo anterior son algunos de los grandes avances que ha tenido la ciencia y la tecnología para lograr mejorar la calidad del aire y por consiguiente la calidad de vida de las personas.

Puedes encontrar mas información sobre este tema en el siguiente enlace:

brainly.com/question/1400149

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Serena, an analyst at an environmental agency, wants to prepare a report using data from the Car Emissions database.
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Remove gray from RGB Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers repres
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Answer:  

Here is the C++ program:  

#include <iostream>   //to use input output functions    

using namespace std;   //to identify objects cin cout    

int main() {   //start of main method    

int red,green,blue,smallest;   //declare variables to store integer values of red,green, blue and to store the smallest value    

cout<<"Enter value for red: ";  //prompts user to enter value for red    

cin>>red;  //reads value for red from user    

cout<<"Enter value for green: ";  //prompts user to enter value for green  

cin>>green; //reads value for green from user    

cout<<"Enter value for blue: "; //prompts user to enter value for blue    

cin>>blue;   //reads value for blue from user    

//computes the smallest value  

if(red<green && red<blue) //if red value is less than green and blue values    

smallest=red;   //red is the smallest so assign value of red to smallest    

else if(green<blue)   //if green value is less than blue value    

smallest=green; //green is the smallest so assign value of green to smallest  

else //this means blue is the smallest    

smallest=blue;  //assign value of blue to smallest    

//removes gray part by subtracting smallest from rgb  

red=red-smallest; //subtract smallest from red    

green=green-smallest; //subtract smallest from green    

blue=blue-smallest; //subtract smallest from blue    

cout<<"red after removing gray part: "<<red<<endl;  //displays amount of red after removing gray    

cout<<"green after removing gray part: "<<green<<endl; //displays amount of green after removing gray  

cout<<"blue after removing gray part: "<<blue<<endl;  } //displays amount of blue after removing gray  

Explanation:  

I will explain the program using an example.    

Lets say user enter 130 as value for red, 50 for green and 130 for blue. So  

red = 130    

green = 50

blue = 130  

First if condition if(red<green && red<blue)   checks if value of red is less than green and blue. Since red=130 so this condition evaluate to false and the program moves to the else if part else if(green<blue) which checks if green is less than blue. This condition evaluates to true as green=50 and blue = 130 so green is less than blue. Hence the body of this else if executes which has the statement: smallest=green;  so the smallest it set to green value.    

smallest = 50    

Now the statement: red=red-smallest; becomes:    

red = 130 - 50    

red = 80    

the statement: green=green-smallest;  becomes:    

green = 50 - 50    

green = 0    

the statement: blue=blue-smallest; becomes:    

blue = 130 - 50    

blue = 80    

So the output of the entire program is:    

red after removing gray part: 80                                                                                                 green after removing gray part: 0                                                                                                blue after removing gray part: 80    

The screenshot of the program along with its output is attached.

5 0
2 years ago
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