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3 years ago

Write a program that takes paragraph from the user and prints all unique words in that paragraph using strings in c++

Computers and Technology

1 answer:

Bezzdna [24]3 years ago

5 0

Answer:

void printUniquedWords(char filename[])

void printUniquedWords(char filename[]) {

void printUniquedWords(char filename[]) { // Whatever your t.text file is

fstream fs(filename);

fstream fs(filename); map<string, int> mp;

fstream fs(filename); map<string, int> mp; // This serves to keep a record of the words

string word;

string word; while (fs >> word)

string word; while (fs >> word) {

string word; while (fs >> word) { // Verifies if this is the first time the word appears hence "unique word"

if (!mp.count(word))

if (!mp.count(word)) mp.insert(make_pair(word, 1));

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++;

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; }

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close();

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1 for (map<string, int> :: iterator p = mp.begin();

if (!mp.count(word)) mp.insert(make_pair(word, 1)); else mp[word]++; } fs.close(); // Traverse map and print all words whose count //is 1 for (map<string, int> :: iterator p = mp.begin(); p != mp.end(); p++)

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} else {
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So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.

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