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ehidna [41]
3 years ago
5

Write a program that takes paragraph from the user and prints all unique words in that paragraph using strings in c++

Computers and Technology
1 answer:
Bezzdna [24]3 years ago
5 0

Answer:

void printUniquedWords(char filename[])

void printUniquedWords(char filename[]) {

void printUniquedWords(char filename[]) {     // Whatever your t.text file is

    fstream fs(filename);

    fstream fs(filename);   

    fstream fs(filename);       

    fstream fs(filename);           map<string, int> mp;

    fstream fs(filename);           map<string, int> mp;   

    fstream fs(filename);           map<string, int> mp;       // This serves to keep a record of the words

    string word;

    string word;     while (fs >> word)

    string word;     while (fs >> word)     {

    string word;     while (fs >> word)     {         // Verifies if this is the first time the word appears hence "unique word"

        if (!mp.count(word))

        if (!mp.count(word))             mp.insert(make_pair(word, 1));

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }   

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();   

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)     {

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)     {         if (p->second == 1)

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)     {         if (p->second == 1)             cout << p->first << endl;

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)     {         if (p->second == 1)             cout << p->first << endl;     }

        if (!mp.count(word))             mp.insert(make_pair(word, 1));         else             mp[word]++;     }       fs.close();       // Traverse map and print all words whose count     //is 1     for (map<string, int> :: iterator p = mp.begin();          p != mp.end(); p++)     {         if (p->second == 1)             cout << p->first << endl;     } }

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Programming challenge description: Given a string comprising just of the characters (,),{,},[,] determine if it is well-formed o
nadezda [96]

Answer:

Employing Java language,

Explanation:

//for using stack data structure

import java.util.Stack;

//class definition

public class BracketMatch {

   //function to find the string is well formed or not

   public static boolean isWellFormed(String str) {

       //variable to store the character value

       char ch;

       //check if the first character itself is the end of the brackets

       if (str.charAt(0) == ')'||str.charAt(0) =='}'||str.charAt(0) ==']')

           return false;

       //creating a stack of character type

       Stack<Character> stack = new Stack<Character>();

       //iterating through the characters in string

       for(int i=0; i < str.length(); i++) {

           //storing the current character from the string in the variable

           ch = str.charAt(i);

           if(ch == '('||ch=='{'||ch=='[')

               //if the character is starting of the brackets push it into stack

               stack.push(ch);

           else if(ch == ')')

               //if it is closing bracket and the stack is empty then the string is not well formatted

               if(stack.empty())

                   return false;

               else if(stack.peek() == '(')

                   stack.pop();

               else

                   return false;

           else if(ch == '}')

               if(stack.empty())

                   return false;

               else if(stack.peek() == '{')

                   stack.pop();

               else

                   return false;

       }

       //returning the stack content, if the string will be well formed the stack would be empty

       //after all the operations

       return stack.empty();

   }

   //main method

   public static void main(String[] args) {

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("{}"));

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("([)]"));

   }

}

5 0
4 years ago
python A pet shop wants to give a discount to its clients if they buy one or more pets. The discount is equal to 20 percent of t
Artyom0805 [142]

Answer:

The following are the program in the Python Programming Language.

#define function

def discount(prices, isPet, nItems):

 # declare and initialize variables to 0

 i = 0

 cost = 0

 pets = 0

 item = 0

 item_Cost = 0

 #set the while loop

 while(i < nItems):

   #check the items of the variable

   if isPet[i]:

     #add and initialize in the cost

     cost += prices[i]

     #increament in the variable by 1

     pets += 1

   #otherwise

   else:

     #add and initialize in the item_Cost

     item_Cost += prices[i]

     #increament in the variable by 1

     item += 1

   #then increment in the variable by 1

   i += 1

 #check the pet is greater than equal to 1  

 #and item is greater than equal to 5

 if(pets >= 1 and item >=5):

   #then, print the message

   print("You receive discount")

   #set discount of the items

   discount = 0.2 * item_Cost

   # calculate bill after deducting discount

   bill = cost + item_Cost - discount

   #print the bill

   print("Final Bill amount is", bill)

 #otherwise

 else:

   #print the message

   print("You do not receive any discount")

   #calculate bill without deducting discount

   bill = cost + item_Cost

   #print the final bill

   print("Final Bill amount is", bill)

#set empty list type variables

price = []

pet = []

#set the infinite loop

while True:

 #get input from the user

 sprice = int(input("Enter the price (-1 to quit): "))

 #check that price is not equal to the -1

 if(sprice != -1):

   #add price in the list

   price.append(sprice)

   #ask for choice from the user

   choice = input("Is it a pet (Y / N)? ")

   #check the choice of the user is y or Y

   if(choice == 'Y' or choice == 'y'):

     # then, add in the pet

     pet.append(True)

   #otherwise

   else:

     #not add in the pet

     pet.append(False)

   print("")

 #break the loop

 else:

   break

#declare variable that store the length

items = len(price)

#call and initialize the variable

discount(price, pet, items)

<u>Output</u>:

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? y

Enter the price (-1 to quit): 69

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 41

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 52

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 74

Is it a pet (Y / N)? n

Enter the price (-1 to quit): -1

You receive discount

Final Bill amount is 361.6

Explanation:

<u>The following are the description of the program</u>.

  • Firstly, define the function 'discount()' and pass the arguments 'prices', 'isPet' and 'nItems' in its parameter.
  • Then, declare and initialize the variables 'i' to 0, 'item_Cost' to 0
  • , item to 0, 'cost' to 0 and 'pets' to 0.
  • Then, set the while loop to add the price of the items and the cost of the pets.
  • Set the if-else conditional statement to check the pet is greater than equal to 1 and the items are greater than equal to 5 then, set the discount and print the bill after deduction.
  • Otherwise, print the bill without deduction.
  • Finally, set two list type variable then, set the infinite while loop that gets input from the user and check that the variable is not equal to -1 then append the data in the list then again check the user input then append in pet otherwise not append in pet and break the loop. Then, set the variable that stores the length of the price and call the following function by passing arguments in its parameter.
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geniusboy [140]

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Explanation:

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