first term.
a= 80
second term. a2=10
so Common ratio r=a2/a =10/80=1/8=0.125
checking for the validity of common ratio.
a2×r=10×1/8=10×0.125=1.25 =a3= Third term.
Hence it is true.
Now 4th Term =1.25/8=0.15625
It can be observed that 4TH term Has digit that is 5 places past the decimal point.
Hence, 0.15625 is the terminating number as per the question.
So the required sum is.
S=a+a2+a3+a4
->S=80+10+1.25+0.15625
->S= 91.40625
Hope it helps...
Regards,
Leukonov/Olegion.
Answer:
x = 3.5y
Step-by-step explanation:
Simplifying
3x + 8y + -5x + -1y = 0
Reorder the terms:
3x + -5x + 8y + -1y = 0
Combine like terms: 3x + -5x = -2x
-2x + 8y + -1y = 0
Combine like terms: 8y + -1y = 7y
-2x + 7y = 0
Solving
-2x + 7y = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-7y' to each side of the equation.
-2x + 7y + -7y = 0 + -7y
Combine like terms: 7y + -7y = 0
-2x + 0 = 0 + -7y
-2x = 0 + -7y
Remove the zero:
-2x = -7y
Divide each side by '-2'.
x = 3.5y
Simplifying
x = 3.5y
1) 26 = 8+v
26 - 8 = v
2) -15 + n = - 9
n = - 9 + 15
n = 15 - 9
n = ?
3) ?
4) -104 = 8x
-104/8 = x
5) 6 = b/18
6 x 18 = b
Answer:
Let AB,BC and CA are the sides of triangle ABC, Given that, Let AB=15cm,BC=27cm and Third side CA=? Then, We know that
CA=BC−AB. CA=15−27.
all in all: CA=12cm
